Add the chapter of backtracking. (#459)

This commit is contained in:
Yudong Jin
2023-04-16 04:52:42 +08:00
committed by GitHub
parent 8bc41bc013
commit 49606fd199
25 changed files with 897 additions and 9 deletions

View File

@ -0,0 +1,68 @@
"""
File: backtrack_find_constrained_path.py
Created Time: 2023-04-15
Author: Krahets (krahets@163.com)
"""
import sys, os.path as osp
sys.path.append(osp.dirname(osp.dirname(osp.abspath(__file__))))
from modules import *
def is_solution(state: list[TreeNode]) -> bool:
"""判断当前状态是否为解"""
return state and state[-1].val == 7
def record_solution(state: list[TreeNode], res: list[list[TreeNode]]):
"""记录解"""
res.append(list(state))
def is_valid(state: list[TreeNode], choice: TreeNode) -> bool:
"""判断在当前状态下,该选择是否合法"""
return choice is not None and choice.val != 3
def make_choice(state: list[TreeNode], choice: TreeNode):
"""更新状态"""
state.append(choice)
def undo_choice(state: list[TreeNode], choice: TreeNode):
"""恢复状态"""
state.pop()
def backtrack(state: list[TreeNode], choices: list[TreeNode], res: list[list[TreeNode]]):
"""回溯算法"""
# 检查是否为解
if is_solution(state):
# 记录解
record_solution(state, res)
return
# 遍历所有选择
for choice in choices:
# 剪枝:检查选择是否合法
if is_valid(state, choice):
# 尝试:做出选择,更新状态
make_choice(state, choice)
backtrack(state, [choice.left, choice.right], res)
# 回退:撤销选择,恢复到之前的状态
undo_choice(state, choice)
"""Driver Code"""
if __name__ == "__main__":
root = list_to_tree([1, 7, 3, 4, 5, 6, 7])
print("\n初始化二叉树")
print_tree(root)
# 回溯算法
res = []
backtrack(state=[], choices=[root], res=res)
print("\n输出所有根节点到节点 7 的路径,要求路径中不包含值为 3 的节点")
for path in res:
print([node.val for node in path])

View File

@ -0,0 +1,43 @@
"""
File: preorder_find_constrained_path.py
Created Time: 2023-04-15
Author: Krahets (krahets@163.com)
"""
import sys, os.path as osp
sys.path.append(osp.dirname(osp.dirname(osp.abspath(__file__))))
from modules import *
def pre_order(root: TreeNode) -> None:
"""前序遍历"""
# 剪枝
if root is None or root.val == 3:
return
# 尝试
path.append(root)
if root.val == 7:
# 记录解
res.append(list(path))
pre_order(root.left)
pre_order(root.right)
# 回退
path.pop()
return
"""Driver Code"""
if __name__ == "__main__":
root = list_to_tree([1, 7, 3, 4, 5, 6, 7])
print("\n初始化二叉树")
print_tree(root)
# 前序遍历
path = list[TreeNode]()
res = list[list[TreeNode]]()
pre_order(root)
print("\n输出所有根节点到节点 7 的路径,且路径中不包含值为 3 的节点")
for path in res:
print([node.val for node in path])

View File

@ -0,0 +1,35 @@
"""
File: preorder_find_nodes.py
Created Time: 2023-04-15
Author: Krahets (krahets@163.com)
"""
import sys, os.path as osp
sys.path.append(osp.dirname(osp.dirname(osp.abspath(__file__))))
from modules import *
def pre_order(root: TreeNode) -> None:
"""前序遍历"""
if root is None:
return
if root.val == 7:
# 记录解
res.append(root)
pre_order(root.left)
pre_order(root.right)
"""Driver Code"""
if __name__ == "__main__":
root = list_to_tree([1, 7, 3, 4, 5, 6, 7])
print("\n初始化二叉树")
print_tree(root)
# 前序遍历
res = list[TreeNode]()
pre_order(root)
print("\n输出所有值为 7 的节点")
print([node.val for node in res])

View File

@ -0,0 +1,42 @@
"""
File: preorder_find_paths.py
Created Time: 2023-04-15
Author: Krahets (krahets@163.com)
"""
import sys, os.path as osp
sys.path.append(osp.dirname(osp.dirname(osp.abspath(__file__))))
from modules import *
def pre_order(root: TreeNode) -> None:
"""前序遍历"""
if root is None:
return
# 尝试
path.append(root)
if root.val == 7:
# 记录解
res.append(list(path))
pre_order(root.left)
pre_order(root.right)
# 回退
path.pop()
return
"""Driver Code"""
if __name__ == "__main__":
root = list_to_tree([1, 7, 3, 4, 5, 6, 7])
print("\n初始化二叉树")
print_tree(root)
# 前序遍历
path = list[TreeNode]()
res = list[list[TreeNode]]()
pre_order(root)
print("\n输出所有根节点到节点 7 的路径")
for path in res:
print([node.val for node in path])