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feat: add the section of the introduction to dynamic programming (#571)
* add the section of the introduction to dynamic programming * add a code comments.
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/**
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* File: climbing_stairs_backtrack.java
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* Created Time: 2023-06-30
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* Author: Krahets (krahets@163.com)
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*/
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package chapter_dynamic_programming;
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import java.util.*;
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public class climbing_stairs_backtrack {
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/* 回溯 */
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public static void backtrack(List<Integer> choices, int state, int n, List<Integer> res) {
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// 当爬到第 n 阶时,方案数量加 1
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if (state == n)
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res.set(0, res.get(0) + 1);
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// 遍历所有选择
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for (Integer choice : choices) {
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// 剪枝:不允许越过第 n 阶
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if (state + choice > n)
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break;
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// 尝试:做出选择,更新状态
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backtrack(choices, state + choice, n, res);
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// 回退
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}
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}
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/* 爬楼梯:回溯 */
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public static int climbingStairsBacktrack(int n) {
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List<Integer> choices = Arrays.asList(1, 2); // 可选择向上爬 1 或 2 阶
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int state = 0; // 从第 0 阶开始爬
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List<Integer> res = new ArrayList<>();
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res.add(0); // 使用 res[0] 记录方案数量
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backtrack(choices, state, n, res);
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return res.get(0);
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}
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public static void main(String[] args) {
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int n = 9;
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int res = climbingStairsBacktrack(n);
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System.out.println(String.format("爬 %d 阶楼梯共有 %d 种方案", n, res));
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}
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}
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/**
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* File: climbing_stairs_dfs.java
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* Created Time: 2023-06-30
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* Author: Krahets (krahets@163.com)
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*/
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package chapter_dynamic_programming;
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public class climbing_stairs_dfs {
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/* 搜索 */
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public static int dfs(int i) {
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// 已知 dp[1] 和 dp[2] ,返回之
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if (i == 1 || i == 2)
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return i;
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// dp[i] = dp[i-1] + dp[i-2]
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int count = dfs(i - 1) + dfs(i - 2);
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return count;
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}
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/* 爬楼梯:搜索 */
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public static int climbingStairsDFS(int n) {
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return dfs(n);
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}
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public static void main(String[] args) {
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int n = 9;
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int res = climbingStairsDFS(n);
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System.out.println(String.format("爬 %d 阶楼梯共有 %d 种方案", n, res));
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}
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}
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/**
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* File: climbing_stairs_dfs_mem.java
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* Created Time: 2023-06-30
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* Author: Krahets (krahets@163.com)
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*/
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package chapter_dynamic_programming;
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import java.util.Arrays;
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public class climbing_stairs_dfs_mem {
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/* 记忆化搜索 */
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public static int dfs(int i, int[] mem) {
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// 已知 dp[1] 和 dp[2] ,返回之
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if (i == 1 || i == 2)
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return i;
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// 若存在记录 dp[i] ,则直接返回之
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if (mem[i] != -1)
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return mem[i];
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// dp[i] = dp[i-1] + dp[i-2]
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int count = dfs(i - 1, mem) + dfs(i - 2, mem);
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// 记录 dp[i]
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mem[i] = count;
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return count;
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}
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/* 爬楼梯:记忆化搜索 */
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public static int climbingStairsDFSMem(int n) {
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// mem[i] 记录爬到第 i 阶的方案总数,-1 代表无记录
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int[] mem = new int[n + 1];
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Arrays.fill(mem, -1);
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return dfs(n, mem);
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}
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public static void main(String[] args) {
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int n = 9;
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int res = climbingStairsDFSMem(n);
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System.out.println(String.format("爬 %d 阶楼梯共有 %d 种方案", n, res));
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}
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}
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/**
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* File: climbing_stairs_dp.java
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* Created Time: 2023-06-30
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* Author: Krahets (krahets@163.com)
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*/
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package chapter_dynamic_programming;
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public class climbing_stairs_dp {
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/* 爬楼梯:动态规划 */
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public static int climbingStairsDP(int n) {
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if (n == 1 || n == 2)
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return n;
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// 初始化 dp 列表,用于存储子问题的解
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int[] dp = new int[n + 1];
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// 初始状态:预设最小子问题的解
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dp[1] = 1;
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dp[2] = 2;
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// 状态转移:从较小子问题逐步求解较大子问题
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for (int i = 3; i <= n; i++) {
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dp[i] = dp[i - 1] + dp[i - 2];
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}
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return dp[n];
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}
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/* 爬楼梯:状态压缩后的动态规划 */
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public static int climbingStairsDPComp(int n) {
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if (n == 1 || n == 2)
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return n;
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int a = 1, b = 2;
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for (int i = 3; i <= n; i++) {
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int tmp = b;
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b = a + b;
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a = tmp;
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}
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return b;
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}
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public static void main(String[] args) {
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int n = 9;
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int res = climbingStairsDP(n);
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System.out.println(String.format("爬 %d 阶楼梯共有 %d 种方案", n, res));
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res = climbingStairsDPComp(n);
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System.out.println(String.format("爬 %d 阶楼梯共有 %d 种方案", n, res));
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}
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}
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/**
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* File: min_cost_climbing_stairs_dp.java
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* Created Time: 2023-06-30
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* Author: Krahets (krahets@163.com)
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*/
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package chapter_dynamic_programming;
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import java.util.Arrays;
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public class min_cost_climbing_stairs_dp {
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/* 爬楼梯最小代价:动态规划 */
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public static int minCostClimbingStairsDP(int[] cost) {
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int n = cost.length - 1;
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if (n == 1 || n == 2)
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return cost[n];
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// 初始化 dp 列表,用于存储子问题的解
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int[] dp = new int[n + 1];
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// 初始状态:预设最小子问题的解
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dp[1] = cost[1];
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dp[2] = cost[2];
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// 状态转移:从较小子问题逐步求解较大子问题
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for (int i = 3; i <= n; i++) {
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dp[i] = Math.min(dp[i - 1], dp[i - 2]) + cost[i];
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}
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return dp[n];
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}
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/* 爬楼梯最小代价:状态压缩后的动态规划 */
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public static int minCostClimbingStairsDPComp(int[] cost) {
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int n = cost.length - 1;
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if (n == 1 || n == 2)
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return cost[n];
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int a = cost[1], b = cost[2];
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for (int i = 3; i <= n; i++) {
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int tmp = b;
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b = Math.min(a, tmp) + cost[i];
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a = tmp;
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}
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return b;
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}
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public static void main(String[] args) {
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int[] cost = { 0, 1, 10, 1, 1, 1, 10, 1, 1, 10, 1 };
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System.out.println(String.format("输入楼梯的代价列表为 %s", Arrays.toString(cost)));
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int res = minCostClimbingStairsDP(cost);
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System.out.println(String.format("爬完楼梯的最低代价为 %d", res));
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res = minCostClimbingStairsDPComp(cost);
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System.out.println(String.format("爬完楼梯的最低代价为 %d", res));
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}
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}
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