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fix: Use int instead of float for the example code of log time complexity (#1164)

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* Use int instead of float for the example code of log time complexity

* Bug fixes

* Bug fixes
This commit is contained in:
Yudong Jin
2024-03-23 02:17:48 +08:00
committed by GitHub
parent fc8473ccfe
commit 3ea91bda99
12 changed files with 69 additions and 69 deletions
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12
codes/java/chapter_computational_complexity/time_complexity.java
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@ -87,7 +87,7 @@ public class time_complexity {
}
/* 对数阶（循环实现） */
static int logarithmic(float n) {
static int logarithmic(int n) {
int count = 0;
while (n > 1) {
n = n / 2;
@ -97,14 +97,14 @@ public class time_complexity {
}
/* 对数阶（递归实现） */
static int logRecur(float n) {
static int logRecur(int n) {
if (n <= 1)
return 0;
return logRecur(n / 2) + 1;
}
/* 线性对数阶 */
static int linearLogRecur(float n) {
static int linearLogRecur(int n) {
if (n <= 1)
return 1;
int count = linearLogRecur(n / 2) + linearLogRecur(n / 2);
@ -153,12 +153,12 @@ public class time_complexity {
count = expRecur(n);
System.out.println("指数阶（递归实现）的操作数量 = " + count);
count = logarithmic((float) n);
count = logarithmic(n);
System.out.println("对数阶（循环实现）的操作数量 = " + count);
count = logRecur((float) n);
count = logRecur(n);
System.out.println("对数阶（递归实现）的操作数量 = " + count);
count = linearLogRecur((float) n);
count = linearLogRecur(n);
System.out.println("线性对数阶（递归实现）的操作数量 = " + count);
count = factorialRecur(n);