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fix: Use int instead of float for the example code of log time complexity (#1164)

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* Use int instead of float for the example code of log time complexity

* Bug fixes

* Bug fixes
This commit is contained in:
Yudong Jin
2024-03-23 02:17:48 +08:00
committed by GitHub
parent fc8473ccfe
commit 3ea91bda99
12 changed files with 69 additions and 69 deletions
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8
codes/go/chapter_computational_complexity/time_complexity.go
View File

@ -87,7 +87,7 @@ func expRecur(n int) int {
}
/* 对数阶（循环实现）*/
func logarithmic(n float64) int {
func logarithmic(n int) int {
count := 0
for n > 1 {
n = n / 2
@ -97,7 +97,7 @@ func logarithmic(n float64) int {
}
/* 对数阶（递归实现）*/
func logRecur(n float64) int {
func logRecur(n int) int {
if n <= 1 {
return 0
}
@ -105,12 +105,12 @@ func logRecur(n float64) int {
}
/* 线性对数阶 */
func linearLogRecur(n float64) int {
func linearLogRecur(n int) int {
if n <= 1 {
return 1
}
count := linearLogRecur(n/2) + linearLogRecur(n/2)
for i := 0.0; i < n; i++ {
for i := 0; i < n; i++ {
count++
}
return count

6
codes/go/chapter_computational_complexity/time_complexity_test.go
View File

@ -35,12 +35,12 @@ func TestTimeComplexity(t *testing.T) {
count = expRecur(n)
fmt.Println("指数阶（递归实现）的操作数量 =", count)
count = logarithmic(float64(n))
count = logarithmic(n)
fmt.Println("对数阶（循环实现）的操作数量 =", count)
count = logRecur(float64(n))
count = logRecur(n)
fmt.Println("对数阶（递归实现）的操作数量 =", count)
count = linearLogRecur(float64(n))
count = linearLogRecur(n)
fmt.Println("线性对数阶（递归实现）的操作数量 =", count)
count = factorialRecur(n)