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fix: Use int instead of float for the example code of log time complexity (#1164)
* Use int instead of float for the example code of log time complexity * Bug fixes * Bug fixes
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@ -86,7 +86,7 @@ int expRecur(int n) {
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}
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/* 对数阶(循环实现) */
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int logarithmic(float n) {
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int logarithmic(int n) {
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int count = 0;
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while (n > 1) {
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n = n / 2;
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@ -96,14 +96,14 @@ int logarithmic(float n) {
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}
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/* 对数阶(递归实现) */
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int logRecur(float n) {
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int logRecur(int n) {
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if (n <= 1)
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return 0;
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return logRecur(n / 2) + 1;
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}
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/* 线性对数阶 */
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int linearLogRecur(float n) {
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int linearLogRecur(int n) {
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if (n <= 1)
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return 1;
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int count = linearLogRecur(n / 2) + linearLogRecur(n / 2);
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@ -153,12 +153,12 @@ int main() {
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count = expRecur(n);
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cout << "指数阶(递归实现)的操作数量 = " << count << endl;
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count = logarithmic((float)n);
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count = logarithmic(n);
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cout << "对数阶(循环实现)的操作数量 = " << count << endl;
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count = logRecur((float)n);
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count = logRecur(n);
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cout << "对数阶(递归实现)的操作数量 = " << count << endl;
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count = linearLogRecur((float)n);
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count = linearLogRecur(n);
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cout << "线性对数阶(递归实现)的操作数量 = " << count << endl;
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count = factorialRecur(n);
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