Add the section of iteration and recursion. (#693)

This commit is contained in:
Yudong Jin
2023-08-24 17:51:41 +08:00
committed by GitHub
parent f524b957d4
commit 3e64f68ae9
15 changed files with 1013 additions and 3 deletions

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add_executable(iteration iteration.cpp)
add_executable(recursion recursion.cpp)
add_executable(space_complexity space_complexity.cpp)
add_executable(time_complexity time_complexity.cpp)
add_executable(worst_best_time_complexity worst_best_time_complexity.cpp)

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/**
* File: iteration.cpp
* Created Time: 2023-08-24
* Author: Krahets (krahets@163.com)
*/
#include "../utils/common.hpp"
/* for 循环 */
int forLoop(int n) {
int res = 0;
// 循环求和 1, 2, ..., n-1, n
for (int i = 1; i <= n; ++i) {
res += i;
}
return res;
}
/* while 循环 */
int whileLoop(int n) {
int res = 0;
int i = 1; // 初始化条件变量
// 循环求和 1, 2, ..., n-1, n
while (i <= n) {
res += i;
i += 1; // 更新条件变量
}
return res;
}
/* while 循环(两次更新) */
int whileLoopII(int n) {
int res = 0;
int i = 1; // 初始化条件变量
// 循环求和 1, 2, 4, 5...
while (i <= n) {
res += i;
i += 1; // 更新条件变量
res += i;
i *= 2; // 更新条件变量
}
return res;
}
/* 双层 for 循环 */
string nestedForLoop(int n) {
ostringstream res;
// 循环 i = 1, 2, ..., n-1, n
for (int i = 1; i <= n; ++i) {
// 循环 j = 1, 2, ..., n-1, n
for (int j = 1; j <= n; ++j) {
res << "(" << i << ", " << j << "), ";
}
}
return res.str();
}
/* Driver Code */
int main() {
int n = 5;
int res;
res = forLoop(n);
cout << "\nfor 循环的求和结果 res = " << res << endl;
res = whileLoop(n);
cout << "\nwhile 循环的求和结果 res = " << res << endl;
res = whileLoopII(n);
cout << "\nwhile 循环(两次更新)求和结果 res = " << res << endl;
string resStr = nestedForLoop(n);
cout << "\n双层 for 循环的遍历结果 " << resStr << endl;
return 0;
}

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/**
* File: recursion.cpp
* Created Time: 2023-08-24
* Author: Krahets (krahets@163.com)
*/
#include "../utils/common.hpp"
/* 递归 */
int recur(int n) {
// 终止条件
if (n == 1)
return 1;
// 递:递归调用
int res = recur(n - 1);
// 归:返回结果
return n + res;
}
/* 尾递归 */
int tailRecur(int n, int res) {
// 终止条件
if (n == 0)
return res;
// 尾递归调用
return tailRecur(n - 1, res + n);
}
/* 斐波那契数列:递归 */
int fib(int n) {
// 终止条件 f(1) = 0, f(2) = 1
if (n == 1 || n == 2)
return n - 1;
// 递归调用 f(n) = f(n-1) + f(n-2)
int res = fib(n - 1) + fib(n - 2);
// 返回结果 f(n)
return res;
}
/* Driver Code */
int main() {
int n = 5;
int res;
res = recur(n);
cout << "\n递归函数的求和结果 res = " << res << endl;
res = tailRecur(n, 0);
cout << "\n尾递归函数的求和结果 res = " << res << endl;
res = fib(n);
cout << "\n斐波那契数列的第 " << n << " 项为 " << res << endl;
return 0;
}