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Add the section of radix sort. (#441)
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codes/python/chapter_sorting/radix_sort.py
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56
codes/python/chapter_sorting/radix_sort.py
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"""
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File: radix_sort.py
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Created Time: 2023-03-26
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Author: Krahets (krahets@163.com)
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"""
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def digit(num: int, exp: int) -> int:
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""" 获取元素 num 的第 k 位,其中 exp = 10^(k-1) """
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# 传入 exp 而非 k 可以避免在此重复执行昂贵的次方计算
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return (num // exp) % 10
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def counting_sort_digit(nums: list[int], exp: int) -> None:
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""" 计数排序(根据 nums 第 k 位排序) """
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# 十进制的位范围为 0~9 ,因此需要长度为 10 的桶
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counter = [0] * 10
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n = len(nums)
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# 统计 0~9 各数字的出现次数
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for i in range(n):
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d = digit(nums[i], exp) # 获取 nums[i] 第 k 位,记为 d
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counter[d] += 1 # 统计数字 d 的出现次数
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# 求前缀和,将“出现个数”转换为“数组索引”
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for i in range(1, 10):
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counter[i] += counter[i - 1]
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# 倒序遍历,根据桶内统计结果,将各元素填入 res
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res = [0] * n
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for i in range(n - 1, -1, -1):
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d = digit(nums[i], exp)
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j = counter[d] - 1 # 获取 d 在数组中的索引 j
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res[j] = nums[i] # 将当前元素填入索引 j
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counter[d] -= 1 # 将 d 的数量减 1
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# 使用结果覆盖原数组 nums
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for i in range(n):
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nums[i] = res[i]
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def radix_sort(nums: list[int]) -> None:
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""" 基数排序 """
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# 获取数组的最大元素,用于判断最大位数
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m = max(nums)
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# 按照从低位到高位的顺序遍历
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exp = 1
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while exp <= m:
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# 对数组元素的第 k 位执行计数排序
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# k = 1 -> exp = 1
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# k = 2 -> exp = 10
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# 即 exp = 10^(k-1)
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counting_sort_digit(nums, exp)
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exp *= 10
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""" Driver Code """
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if __name__ == '__main__':
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# 基数排序
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nums = [10546151, 35663510, 42865989, 34862445, 81883077,
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88906420, 72429244, 30524779, 82060337, 63832996]
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radix_sort(nums)
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print("基数排序完成后 nums =", nums)
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