Add the section of radix sort. (#441)

This commit is contained in:
Yudong Jin
2023-03-26 22:02:37 +08:00
committed by GitHub
parent 4830dffd26
commit 34a1bca627
16 changed files with 405 additions and 142 deletions

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"""
File: radix_sort.py
Created Time: 2023-03-26
Author: Krahets (krahets@163.com)
"""
def digit(num: int, exp: int) -> int:
""" 获取元素 num 的第 k 位,其中 exp = 10^(k-1) """
# 传入 exp 而非 k 可以避免在此重复执行昂贵的次方计算
return (num // exp) % 10
def counting_sort_digit(nums: list[int], exp: int) -> None:
""" 计数排序(根据 nums 第 k 位排序) """
# 十进制的位范围为 0~9 ,因此需要长度为 10 的桶
counter = [0] * 10
n = len(nums)
# 统计 0~9 各数字的出现次数
for i in range(n):
d = digit(nums[i], exp) # 获取 nums[i] 第 k 位,记为 d
counter[d] += 1 # 统计数字 d 的出现次数
# 求前缀和,将“出现个数”转换为“数组索引”
for i in range(1, 10):
counter[i] += counter[i - 1]
# 倒序遍历,根据桶内统计结果,将各元素填入 res
res = [0] * n
for i in range(n - 1, -1, -1):
d = digit(nums[i], exp)
j = counter[d] - 1 # 获取 d 在数组中的索引 j
res[j] = nums[i] # 将当前元素填入索引 j
counter[d] -= 1 # 将 d 的数量减 1
# 使用结果覆盖原数组 nums
for i in range(n):
nums[i] = res[i]
def radix_sort(nums: list[int]) -> None:
""" 基数排序 """
# 获取数组的最大元素,用于判断最大位数
m = max(nums)
# 按照从低位到高位的顺序遍历
exp = 1
while exp <= m:
# 对数组元素的第 k 位执行计数排序
# k = 1 -> exp = 1
# k = 2 -> exp = 10
# 即 exp = 10^(k-1)
counting_sort_digit(nums, exp)
exp *= 10
""" Driver Code """
if __name__ == '__main__':
# 基数排序
nums = [10546151, 35663510, 42865989, 34862445, 81883077,
88906420, 72429244, 30524779, 82060337, 63832996]
radix_sort(nums)
print("基数排序完成后 nums =", nums)