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<h1 id="122">12.2 分治搜索策略<a class="headerlink" href="#122" title="Permanent link">¶</a></h1>
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furnished to do so, subject to the following conditions:
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The above copyright notice and this permission notice shall be included in
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all copies or substantial portions of the Software.
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THE SOFTWARE IS PROVIDED "AS IS", WITHOUT WARRANTY OF ANY KIND, EXPRESS OR
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IMPLIED, INCLUDING BUT NOT LIMITED TO THE WARRANTIES OF MERCHANTABILITY,
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FITNESS FOR A PARTICULAR PURPOSE AND NON-INFRINGEMENT. IN NO EVENT SHALL THE
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AUTHORS OR COPYRIGHT HOLDERS BE LIABLE FOR ANY CLAIM, DAMAGES OR OTHER
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@ -3477,6 +3502,13 @@
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<h1 id="123">12.3 构建二叉树问题<a class="headerlink" href="#123" title="Permanent link">¶</a></h1>
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<div class="admonition question">
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<p class="admonition-title">Question</p>
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@ -3919,11 +3951,73 @@
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||||
<p>设树的节点数量为 <span class="arithmatex">\(n\)</span> ,初始化每一个节点(执行一个递归函数 <code>dfs()</code> )使用 <span class="arithmatex">\(O(1)\)</span> 时间。<strong>因此总体时间复杂度为 <span class="arithmatex">\(O(n)\)</span></strong> 。</p>
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||||
<p>哈希表存储 <code>inorder</code> 元素到索引的映射,空间复杂度为 <span class="arithmatex">\(O(n)\)</span> 。最差情况下,即二叉树退化为链表时,递归深度达到 <span class="arithmatex">\(n\)</span> ,使用 <span class="arithmatex">\(O(n)\)</span> 的栈帧空间。<strong>因此总体空间复杂度为 <span class="arithmatex">\(O(n)\)</span></strong> 。</p>
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Permission is hereby granted, free of charge, to any person obtaining a copy
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deal in the Software without restriction, including without limitation the
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|
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|
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furnished to do so, subject to the following conditions:
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The above copyright notice and this permission notice shall be included in
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all copies or substantial portions of the Software.
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THE SOFTWARE IS PROVIDED "AS IS", WITHOUT WARRANTY OF ANY KIND, EXPRESS OR
|
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IMPLIED, INCLUDING BUT NOT LIMITED TO THE WARRANTIES OF MERCHANTABILITY,
|
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FITNESS FOR A PARTICULAR PURPOSE AND NON-INFRINGEMENT. IN NO EVENT SHALL THE
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AUTHORS OR COPYRIGHT HOLDERS BE LIABLE FOR ANY CLAIM, DAMAGES OR OTHER
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|
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|
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AUTHORS OR COPYRIGHT HOLDERS BE LIABLE FOR ANY CLAIM, DAMAGES OR OTHER
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|
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|
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|
||||
<!-- Page content -->
|
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<h1 id="121">12.1 分治算法<a class="headerlink" href="#121" title="Permanent link">¶</a></h1>
|
||||
<p>「分治 divide and conquer」,全称分而治之,是一种非常重要且常见的算法策略。分治通常基于递归实现,包括“分”和“治”两个步骤。</p>
|
||||
<ol>
|
||||
@ -3580,11 +3612,73 @@ n(n - 4) & > 0
|
||||
</ul>
|
||||
<p>可以看出,<strong>分治是一种“润物细无声”的算法思想</strong>,隐含在各种算法与数据结构之中。</p>
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<h1 id="124">12.4 汉诺塔问题<a class="headerlink" href="#124" title="Permanent link">¶</a></h1>
|
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<p>在归并排序和构建二叉树中,我们都是将原问题分解为两个规模为原问题一半的子问题。然而对于汉诺塔问题,我们采用不同的分解策略。</p>
|
||||
<div class="admonition question">
|
||||
@ -3907,11 +3939,73 @@
|
||||
<p>然而,即使僧侣们每秒钟移动一次,总共需要大约 <span class="arithmatex">\(2^{64} \approx 1.84×10^{19}\)</span> 秒,合约 <span class="arithmatex">\(5850\)</span> 亿年,远远超过了现在对宇宙年龄的估计。所以,倘若这个传说是真的,我们应该不需要担心世界末日的到来。</p>
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<h1 id="12">第 12 章 分治<a class="headerlink" href="#12" title="Permanent link">¶</a></h1>
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<h1 id="125">12.5 小结<a class="headerlink" href="#125" title="Permanent link">¶</a></h1>
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<li>分治算法是一种常见的算法设计策略,包括分(划分)和治(合并)两个阶段,通常基于递归实现。</li>
|
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@ -3388,11 +3420,73 @@
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<li>在汉诺塔问题中,一个规模为 <span class="arithmatex">\(n\)</span> 的问题可以被划分为两个规模为 <span class="arithmatex">\(n-1\)</span> 的子问题和一个规模为 <span class="arithmatex">\(1\)</span> 的子问题。按顺序解决这三个子问题后,原问题随之得到解决。</li>
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