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feat: add rust codes for array binary tree (#654)
* feat: add rust codes for array binary tree * update tree_node.rs * update: add implementation of vec_to_tree and tree_to_vec * update tree_node.rs * Update tree_node.rs --------- Co-authored-by: Yudong Jin <krahets@163.com>
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199
codes/rust/chapter_tree/array_binary_tree.rs
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199
codes/rust/chapter_tree/array_binary_tree.rs
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/*
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* File: array_binary_tree.rs
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* Created Time: 2023-07-25
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* Author: night-cruise (2586447362@qq.com)
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*/
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include!("../include/include.rs");
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/* 数组表示下的二叉树类 */
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struct ArrayBinaryTree {
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tree: Vec<Option<i32>>,
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}
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impl ArrayBinaryTree {
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/* 构造方法 */
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fn new(arr: Vec<Option<i32>>) -> Self {
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Self { tree: arr }
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}
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/* 节点数量 */
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fn size(&self) -> i32 {
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self.tree.len() as i32
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}
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/* 获取索引为 i 节点的值 */
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fn val(&self, i: i32) -> Option<i32> {
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// 若索引越界,则返回 None ,代表空位
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if i < 0 || i >= self.size() {
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None
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} else {
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self.tree[i as usize]
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}
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}
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/* 获取索引为 i 节点的左子节点的索引 */
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fn left(&self, i: i32) -> i32 {
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2 * i + 1
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}
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/* 获取索引为 i 节点的右子节点的索引 */
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fn right(&self, i: i32) -> i32 {
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2 * i + 2
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}
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/* 获取索引为 i 节点的父节点的索引 */
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fn parent(&self, i: i32) -> i32 {
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(i - 1) / 2
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}
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/* 层序遍历 */
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fn level_order(&self) -> Vec<i32> {
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let mut res = vec![];
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// 直接遍历数组
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for i in 0..self.size() {
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if let Some(val) = self.val(i) {
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res.push(val)
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}
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}
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res
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}
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/* 深度优先遍历 */
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fn dfs(&self, i: i32, order: &str, res: &mut Vec<i32>) {
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if self.val(i).is_none() {
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return;
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}
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let val = self.val(i).unwrap();
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// 前序遍历
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if order == "pre" {
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res.push(val);
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}
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self.dfs(self.left(i), order, res);
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// 中序遍历
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if order == "in" {
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res.push(val);
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}
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self.dfs(self.right(i), order, res);
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// 后序遍历
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if order == "post" {
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res.push(val);
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}
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}
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/* 前序遍历 */
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fn pre_order(&self) -> Vec<i32> {
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let mut res = vec![];
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self.dfs(0, "pre", &mut res);
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res
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}
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/* 中序遍历 */
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fn in_order(&self) -> Vec<i32> {
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let mut res = vec![];
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self.dfs(0, "in", &mut res);
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res
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}
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/* 后序遍历 */
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fn post_order(&self) -> Vec<i32> {
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let mut res = vec![];
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self.dfs(0, "post", &mut res);
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res
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}
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}
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/* Driver Code */
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fn main() {
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// 初始化二叉树
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// 这里借助了一个从数组直接生成二叉树的函数
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let arr = vec![
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Some(1),
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Some(2),
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Some(3),
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Some(4),
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None,
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Some(6),
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Some(7),
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Some(8),
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Some(9),
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None,
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None,
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Some(12),
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None,
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None,
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Some(15),
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];
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let root = tree_node::vec_to_tree(arr.clone()).unwrap();
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println!("\n初始化二叉树\n");
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println!("二叉树的数组表示:");
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println!(
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"[{}]",
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arr.iter()
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.map(|&val| if let Some(val) = val {
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format!("{val}")
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} else {
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"null".to_string()
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})
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.collect::<Vec<String>>()
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.join(", ")
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);
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println!("二叉树的链表表示:");
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print_util::print_tree(&root);
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// 数组表示下的二叉树类
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let abt = ArrayBinaryTree::new(arr);
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// 访问节点
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let i = 1;
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let l = abt.left(i);
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let r = abt.right(i);
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let p = abt.parent(i);
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println!(
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"\n当前节点的索引为 {} ,值为 {}",
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i,
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if let Some(val) = abt.val(i) {
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format!("{val}")
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} else {
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"null".to_string()
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}
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);
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println!(
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"其左子节点的索引为 {} ,值为 {}",
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l,
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if let Some(val) = abt.val(l) {
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format!("{val}")
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} else {
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"null".to_string()
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}
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);
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println!(
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"其右子节点的索引为 {} ,值为 {}",
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r,
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if let Some(val) = abt.val(r) {
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format!("{val}")
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} else {
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"null".to_string()
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}
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);
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println!(
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"其父节点的索引为 {} ,值为 {}",
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p,
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if let Some(val) = abt.val(p) {
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format!("{val}")
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} else {
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"null".to_string()
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}
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);
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// 遍历树
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let mut res = abt.level_order();
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println!("\n层序遍历为:{:?}", res);
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res = abt.pre_order();
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println!("前序遍历为:{:?}", res);
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res = abt.in_order();
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println!("中序遍历为:{:?}", res);
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res = abt.post_order();
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println!("后序遍历为:{:?}", res);
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}
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