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[mypy] Add/fix type annotations for backtracking algorithms (#4055)
* Fix mypy errors for backtracking algorithms * Fix CI failure
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@ -75,14 +75,14 @@ Applying this two formulas we can check if a queen in some position is being att
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for another one or vice versa.
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"""
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from __future__ import annotations
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from typing import List
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def depth_first_search(
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possible_board: list[int],
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diagonal_right_collisions: list[int],
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diagonal_left_collisions: list[int],
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boards: list[list[str]],
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possible_board: List[int],
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diagonal_right_collisions: List[int],
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diagonal_left_collisions: List[int],
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boards: List[List[str]],
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n: int,
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) -> None:
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"""
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@ -94,40 +94,33 @@ def depth_first_search(
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['. . Q . ', 'Q . . . ', '. . . Q ', '. Q . . ']
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"""
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""" Get next row in the current board (possible_board) to fill it with a queen """
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# Get next row in the current board (possible_board) to fill it with a queen
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row = len(possible_board)
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"""
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If row is equal to the size of the board it means there are a queen in each row in
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the current board (possible_board)
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"""
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# If row is equal to the size of the board it means there are a queen in each row in
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# the current board (possible_board)
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if row == n:
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"""
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We convert the variable possible_board that looks like this: [1, 3, 0, 2] to
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this: ['. Q . . ', '. . . Q ', 'Q . . . ', '. . Q . ']
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"""
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possible_board = [". " * i + "Q " + ". " * (n - 1 - i) for i in possible_board]
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boards.append(possible_board)
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# We convert the variable possible_board that looks like this: [1, 3, 0, 2] to
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# this: ['. Q . . ', '. . . Q ', 'Q . . . ', '. . Q . ']
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boards.append([". " * i + "Q " + ". " * (n - 1 - i) for i in possible_board])
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return
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""" We iterate each column in the row to find all possible results in each row """
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# We iterate each column in the row to find all possible results in each row
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for col in range(n):
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"""
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We apply that we learned previously. First we check that in the current board
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(possible_board) there are not other same value because if there is it means
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that there are a collision in vertical. Then we apply the two formulas we
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learned before:
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45º: y - x = b or 45: row - col = b
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135º: y + x = b or row + col = b.
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And we verify if the results of this two formulas not exist in their variables
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respectively. (diagonal_right_collisions, diagonal_left_collisions)
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If any or these are True it means there is a collision so we continue to the
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next value in the for loop.
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"""
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# We apply that we learned previously. First we check that in the current board
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# (possible_board) there are not other same value because if there is it means
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# that there are a collision in vertical. Then we apply the two formulas we
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# learned before:
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#
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# 45º: y - x = b or 45: row - col = b
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# 135º: y + x = b or row + col = b.
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#
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# And we verify if the results of this two formulas not exist in their variables
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# respectively. (diagonal_right_collisions, diagonal_left_collisions)
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#
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# If any or these are True it means there is a collision so we continue to the
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# next value in the for loop.
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if (
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col in possible_board
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or row - col in diagonal_right_collisions
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@ -135,7 +128,7 @@ def depth_first_search(
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):
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continue
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""" If it is False we call dfs function again and we update the inputs """
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# If it is False we call dfs function again and we update the inputs
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depth_first_search(
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possible_board + [col],
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diagonal_right_collisions + [row - col],
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@ -146,10 +139,10 @@ def depth_first_search(
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def n_queens_solution(n: int) -> None:
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boards = []
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boards: List[List[str]] = []
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depth_first_search([], [], [], boards, n)
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""" Print all the boards """
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# Print all the boards
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for board in boards:
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for column in board:
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print(column)
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