psf/black code formatting (#1277)

This commit is contained in:
William Zhang
2019-10-05 01:14:13 -04:00
committed by Christian Clauss
parent 07f04a2e55
commit 9eac17a408
291 changed files with 6014 additions and 4571 deletions

View File

@@ -20,12 +20,9 @@ Time Complexity : O(n/m)
class BoyerMooreSearch:
def __init__(self, text, pattern):
self.text, self.pattern = text, pattern
self.textLen, self.patLen = len(text), len(pattern)
def match_in_pattern(self, char):
""" finds the index of char in pattern in reverse order
@@ -36,14 +33,13 @@ class BoyerMooreSearch:
Returns :
i (int): index of char from last in pattern
-1 (int): if char is not found in pattern
"""
"""
for i in range(self.patLen-1, -1, -1):
for i in range(self.patLen - 1, -1, -1):
if char == self.pattern[i]:
return i
return -1
def mismatch_in_text(self, currentPos):
""" finds the index of mis-matched character in text when compared with pattern from last
@@ -55,14 +51,13 @@ class BoyerMooreSearch:
-1 (int): if there is no mis-match between pattern and text block
"""
for i in range(self.patLen-1, -1, -1):
for i in range(self.patLen - 1, -1, -1):
if self.pattern[i] != self.text[currentPos + i]:
return currentPos + i
return -1
def bad_character_heuristic(self):
# searches pattern in text and returns index positions
# searches pattern in text and returns index positions
positions = []
for i in range(self.textLen - self.patLen + 1):
mismatch_index = self.mismatch_in_text(i)
@@ -70,12 +65,14 @@ class BoyerMooreSearch:
positions.append(i)
else:
match_index = self.match_in_pattern(self.text[mismatch_index])
i = mismatch_index - match_index #shifting index lgtm [py/multiple-definition]
i = (
mismatch_index - match_index
) # shifting index lgtm [py/multiple-definition]
return positions
text = "ABAABA"
pattern = "AB"
pattern = "AB"
bms = BoyerMooreSearch(text, pattern)
positions = bms.bad_character_heuristic()
@@ -84,5 +81,3 @@ if len(positions) == 0:
else:
print("Pattern found in following positions: ")
print(positions)

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@@ -46,14 +46,14 @@ def get_failure_array(pattern):
if pattern[i] == pattern[j]:
i += 1
elif i > 0:
i = failure[i-1]
i = failure[i - 1]
continue
j += 1
failure.append(i)
return failure
if __name__ == '__main__':
if __name__ == "__main__":
# Test 1)
pattern = "abc1abc12"
text1 = "alskfjaldsabc1abc1abc12k23adsfabcabc"

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@@ -64,10 +64,13 @@ def levenshtein_distance(first_word, second_word):
return previous_row[-1]
if __name__ == '__main__':
first_word = input('Enter the first word:\n').strip()
second_word = input('Enter the second word:\n').strip()
if __name__ == "__main__":
first_word = input("Enter the first word:\n").strip()
second_word = input("Enter the second word:\n").strip()
result = levenshtein_distance(first_word, second_word)
print('Levenshtein distance between {} and {} is {}'.format(
first_word, second_word, result))
print(
"Levenshtein distance between {} and {} is {}".format(
first_word, second_word, result
)
)

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@@ -1,10 +1,15 @@
# calculate palindromic length from center with incrementing difference
def palindromic_length( center, diff, string):
if center-diff == -1 or center+diff == len(string) or string[center-diff] != string[center+diff] :
def palindromic_length(center, diff, string):
if (
center - diff == -1
or center + diff == len(string)
or string[center - diff] != string[center + diff]
):
return 0
return 1 + palindromic_length(center, diff+1, string)
return 1 + palindromic_length(center, diff + 1, string)
def palindromic_string( input_string ):
def palindromic_string(input_string):
"""
Manachers algorithm which finds Longest Palindromic Substring in linear time.
@@ -16,37 +21,36 @@ def palindromic_string( input_string ):
3. return output_string from center - max_length to center + max_length and remove all "|"
"""
max_length = 0
# if input_string is "aba" than new_input_string become "a|b|a"
new_input_string = ""
output_string = ""
# append each character + "|" in new_string for range(0, length-1)
for i in input_string[:len(input_string)-1] :
for i in input_string[: len(input_string) - 1]:
new_input_string += i + "|"
#append last character
# append last character
new_input_string += input_string[-1]
# for each character in new_string find corresponding palindromic string
for i in range(len(new_input_string)) :
for i in range(len(new_input_string)):
# get palindromic length from ith position
length = palindromic_length(i, 1, new_input_string)
# update max_length and start position
if max_length < length :
if max_length < length:
max_length = length
start = i
#create that string
for i in new_input_string[start-max_length:start+max_length+1] :
# create that string
for i in new_input_string[start - max_length : start + max_length + 1]:
if i != "|":
output_string += i
return output_string
if __name__ == '__main__':
if __name__ == "__main__":
n = input()
print(palindromic_string(n))

View File

@@ -1,114 +1,118 @@
'''
"""
Algorithm for calculating the most cost-efficient sequence for converting one string into another.
The only allowed operations are
---Copy character with cost cC
---Replace character with cost cR
---Delete character with cost cD
---Insert character with cost cI
'''
"""
def compute_transform_tables(X, Y, cC, cR, cD, cI):
X = list(X)
Y = list(Y)
m = len(X)
n = len(Y)
X = list(X)
Y = list(Y)
m = len(X)
n = len(Y)
costs = [[0 for _ in range(n+1)] for _ in range(m+1)]
ops = [[0 for _ in range(n+1)] for _ in range(m+1)]
costs = [[0 for _ in range(n + 1)] for _ in range(m + 1)]
ops = [[0 for _ in range(n + 1)] for _ in range(m + 1)]
for i in range(1, m+1):
costs[i][0] = i*cD
ops[i][0] = 'D%c' % X[i-1]
for i in range(1, m + 1):
costs[i][0] = i * cD
ops[i][0] = "D%c" % X[i - 1]
for i in range(1, n+1):
costs[0][i] = i*cI
ops[0][i] = 'I%c' % Y[i-1]
for i in range(1, n + 1):
costs[0][i] = i * cI
ops[0][i] = "I%c" % Y[i - 1]
for i in range(1, m+1):
for j in range(1, n+1):
if X[i-1] == Y[j-1]:
costs[i][j] = costs[i-1][j-1] + cC
ops[i][j] = 'C%c' % X[i-1]
else:
costs[i][j] = costs[i-1][j-1] + cR
ops[i][j] = 'R%c' % X[i-1] + str(Y[j-1])
for i in range(1, m + 1):
for j in range(1, n + 1):
if X[i - 1] == Y[j - 1]:
costs[i][j] = costs[i - 1][j - 1] + cC
ops[i][j] = "C%c" % X[i - 1]
else:
costs[i][j] = costs[i - 1][j - 1] + cR
ops[i][j] = "R%c" % X[i - 1] + str(Y[j - 1])
if costs[i-1][j] + cD < costs[i][j]:
costs[i][j] = costs[i-1][j] + cD
ops[i][j] = 'D%c' % X[i-1]
if costs[i - 1][j] + cD < costs[i][j]:
costs[i][j] = costs[i - 1][j] + cD
ops[i][j] = "D%c" % X[i - 1]
if costs[i][j-1] + cI < costs[i][j]:
costs[i][j] = costs[i][j-1] + cI
ops[i][j] = 'I%c' % Y[j-1]
if costs[i][j - 1] + cI < costs[i][j]:
costs[i][j] = costs[i][j - 1] + cI
ops[i][j] = "I%c" % Y[j - 1]
return costs, ops
return costs, ops
def assemble_transformation(ops, i, j):
if i == 0 and j == 0:
seq = []
return seq
else:
if ops[i][j][0] == 'C' or ops[i][j][0] == 'R':
seq = assemble_transformation(ops, i-1, j-1)
seq.append(ops[i][j])
return seq
elif ops[i][j][0] == 'D':
seq = assemble_transformation(ops, i-1, j)
seq.append(ops[i][j])
return seq
else:
seq = assemble_transformation(ops, i, j-1)
seq.append(ops[i][j])
return seq
if i == 0 and j == 0:
seq = []
return seq
else:
if ops[i][j][0] == "C" or ops[i][j][0] == "R":
seq = assemble_transformation(ops, i - 1, j - 1)
seq.append(ops[i][j])
return seq
elif ops[i][j][0] == "D":
seq = assemble_transformation(ops, i - 1, j)
seq.append(ops[i][j])
return seq
else:
seq = assemble_transformation(ops, i, j - 1)
seq.append(ops[i][j])
return seq
if __name__ == '__main__':
_, operations = compute_transform_tables('Python', 'Algorithms', -1, 1, 2, 2)
m = len(operations)
n = len(operations[0])
sequence = assemble_transformation(operations, m-1, n-1)
if __name__ == "__main__":
_, operations = compute_transform_tables("Python", "Algorithms", -1, 1, 2, 2)
string = list('Python')
i = 0
cost = 0
m = len(operations)
n = len(operations[0])
sequence = assemble_transformation(operations, m - 1, n - 1)
with open('min_cost.txt', 'w') as file:
for op in sequence:
print(''.join(string))
string = list("Python")
i = 0
cost = 0
if op[0] == 'C':
file.write('%-16s' % 'Copy %c' % op[1])
file.write('\t\t\t' + ''.join(string))
file.write('\r\n')
with open("min_cost.txt", "w") as file:
for op in sequence:
print("".join(string))
cost -= 1
elif op[0] == 'R':
string[i] = op[2]
if op[0] == "C":
file.write("%-16s" % "Copy %c" % op[1])
file.write("\t\t\t" + "".join(string))
file.write("\r\n")
file.write('%-16s' % ('Replace %c' % op[1] + ' with ' + str(op[2])))
file.write('\t\t' + ''.join(string))
file.write('\r\n')
cost -= 1
elif op[0] == "R":
string[i] = op[2]
cost += 1
elif op[0] == 'D':
string.pop(i)
file.write("%-16s" % ("Replace %c" % op[1] + " with " + str(op[2])))
file.write("\t\t" + "".join(string))
file.write("\r\n")
file.write('%-16s' % 'Delete %c' % op[1])
file.write('\t\t\t' + ''.join(string))
file.write('\r\n')
cost += 1
elif op[0] == "D":
string.pop(i)
cost += 2
else:
string.insert(i, op[1])
file.write("%-16s" % "Delete %c" % op[1])
file.write("\t\t\t" + "".join(string))
file.write("\r\n")
file.write('%-16s' % 'Insert %c' % op[1])
file.write('\t\t\t' + ''.join(string))
file.write('\r\n')
cost += 2
else:
string.insert(i, op[1])
cost += 2
file.write("%-16s" % "Insert %c" % op[1])
file.write("\t\t\t" + "".join(string))
file.write("\r\n")
i += 1
cost += 2
print(''.join(string))
print('Cost: ', cost)
i += 1
file.write('\r\nMinimum cost: ' + str(cost))
print("".join(string))
print("Cost: ", cost)
file.write("\r\nMinimum cost: " + str(cost))

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@@ -7,23 +7,26 @@ Complexity : O(n*m)
n=length of main string
m=length of pattern string
"""
def naivePatternSearch(mainString,pattern):
patLen=len(pattern)
strLen=len(mainString)
position=[]
for i in range(strLen-patLen+1):
match_found=True
def naivePatternSearch(mainString, pattern):
patLen = len(pattern)
strLen = len(mainString)
position = []
for i in range(strLen - patLen + 1):
match_found = True
for j in range(patLen):
if mainString[i+j]!=pattern[j]:
match_found=False
if mainString[i + j] != pattern[j]:
match_found = False
break
if match_found:
position.append(i)
return position
mainString="ABAAABCDBBABCDDEBCABC"
pattern="ABC"
position=naivePatternSearch(mainString,pattern)
mainString = "ABAAABCDBBABCDDEBCABC"
pattern = "ABC"
position = naivePatternSearch(mainString, pattern)
print("Pattern found in position ")
for x in position:
print(x)
print(x)