snake_case all the things

This commit is contained in:
Alex Brown
2018-10-19 17:14:25 -05:00
parent 564179a0ec
commit 91fccecb56
96 changed files with 0 additions and 1373 deletions

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'''
Problem:
Each new term in the Fibonacci sequence is generated by adding the previous two terms. By starting with 1 and 2,
the first 10 terms will be:
1,2,3,5,8,13,21,34,55,89,..
By considering the terms in the Fibonacci sequence whose values do not exceed n, find the sum of the even-valued terms.
e.g. for n=10, we have {2,8}, sum is 10.
'''
from __future__ import print_function
try:
raw_input # Python 2
except NameError:
raw_input = input # Python 3
n = int(raw_input().strip())
i=1
j=2
sum=0
while(j<=n):
if((j&1)==0): #can also use (j%2==0)
sum+=j
temp=i
i=j
j=temp+i
print(sum)

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def fib(n):
a, b, s = 0, 1, 0
while b < n:
if b % 2 == 0 and b < n: s += b
a, b = b, a+b
ls.append(s)
T = int(input().strip())
ls = []
for _ in range(T):
fib(int(input().strip()))
print(ls, sep = '\n')

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'''
Problem:
Each new term in the Fibonacci sequence is generated by adding the previous two terms.
0,1,1,2,3,5,8,13,21,34,55,89,..
Every third term from 0 is even So using this I have written a simple code
By considering the terms in the Fibonacci sequence whose values do not exceed n, find the sum of the even-valued terms.
e.g. for n=10, we have {2,8}, sum is 10.
'''
"""Python 3"""
n = int(raw_input())
a=0
b=2
count=0
while 4*b+a<n:
c=4*b+a
a=b
b=c
count=count+a
print(count+b)