snake_case all the things

This commit is contained in:
Alex Brown
2018-10-19 17:14:25 -05:00
parent 564179a0ec
commit 91fccecb56
96 changed files with 0 additions and 1373 deletions

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'''
Problem Statement:
If we list all the natural numbers below 10 that are multiples of 3 or 5,
we get 3,5,6 and 9. The sum of these multiples is 23.
Find the sum of all the multiples of 3 or 5 below N.
'''
from __future__ import print_function
try:
raw_input # Python 2
except NameError:
raw_input = input # Python 3
n = int(raw_input().strip())
sum=0
for a in range(3,n):
if(a%3==0 or a%5==0):
sum+=a
print(sum)

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'''
Problem Statement:
If we list all the natural numbers below 10 that are multiples of 3 or 5,
we get 3,5,6 and 9. The sum of these multiples is 23.
Find the sum of all the multiples of 3 or 5 below N.
'''
from __future__ import print_function
try:
raw_input # Python 2
except NameError:
raw_input = input # Python 3
n = int(raw_input().strip())
sum = 0
terms = (n-1)//3
sum+= ((terms)*(6+(terms-1)*3))//2 #sum of an A.P.
terms = (n-1)//5
sum+= ((terms)*(10+(terms-1)*5))//2
terms = (n-1)//15
sum-= ((terms)*(30+(terms-1)*15))//2
print(sum)

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from __future__ import print_function
'''
Problem Statement:
If we list all the natural numbers below 10 that are multiples of 3 or 5,
we get 3,5,6 and 9. The sum of these multiples is 23.
Find the sum of all the multiples of 3 or 5 below N.
'''
'''
This solution is based on the pattern that the successive numbers in the series follow: 0+3,+2,+1,+3,+1,+2,+3.
'''
try:
raw_input # Python 2
except NameError:
raw_input = input # Python 3
n = int(raw_input().strip())
sum=0
num=0
while(1):
num+=3
if(num>=n):
break
sum+=num
num+=2
if(num>=n):
break
sum+=num
num+=1
if(num>=n):
break
sum+=num
num+=3
if(num>=n):
break
sum+=num
num+=1
if(num>=n):
break
sum+=num
num+=2
if(num>=n):
break
sum+=num
num+=3
if(num>=n):
break
sum+=num
print(sum);

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def mulitples(limit):
xmulti = []
zmulti = []
z = 3
x = 5
temp = 1
while True:
result = z * temp
if (result < limit):
zmulti.append(result)
temp += 1
else:
temp = 1
break
while True:
result = x * temp
if (result < limit):
xmulti.append(result)
temp += 1
else:
break
collection = list(set(xmulti+zmulti))
return (sum(collection))
print (mulitples(1000))