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[fixed] unused variable, standalone running, import doctest module (#4673)

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* [fixed] unused variable, standalone running, import doctest module

information [standalone running](https://www.geeksforgeeks.org/what-does-the-if-__name__-__main__-do/)

Signed-off-by: slowy07 <slowy.arfy@gmail.com>

* Update other/fischer_yates_shuffle.py

Co-authored-by: Christian Clauss <cclauss@me.com>

* [fixed] change to tuple and fixing callfunction

Signed-off-by: slowy07 <slowy.arfy@gmail.com>

* Update matrix/spiral_print.py

Co-authored-by: Christian Clauss <cclauss@me.com>

* Update matrix/spiral_print.py

Co-authored-by: Christian Clauss <cclauss@me.com>

* fixing

Co-authored-by: Christian Clauss <cclauss@me.com>

* [fixed] sprial matrix

Signed-off-by: slowy07 <slowy.arfy@gmail.com>

* Update spiral_print.py

* Update spiral_print.py

* Update spiral_print.py

* Update spiral_print.py

Co-authored-by: Christian Clauss <cclauss@me.com>
This commit is contained in:
arfy slowy
2021-08-29 01:07:10 +07:00
committed by GitHub
parent 46e56fa6f2
commit 8e5c3536c7
3 changed files with 23 additions and 20 deletions
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34
matrix/spiral_print.py
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@ -4,36 +4,35 @@ This problem has been solved through recursive way.
Matrix must satisfy below conditions
i) matrix should be only one or two dimensional
ii)column of all the row should be equal
ii) number of column of all rows should be equal
"""
from collections.abc import Iterable
def checkMatrix(a):
def check_matrix(matrix):
# must be
if type(a) == list and len(a) > 0:
if type(a[0]) == list:
prevLen = 0
for i in a:
if prevLen == 0:
prevLen = len(i)
result = True
elif prevLen == len(i):
if matrix and isinstance(matrix, Iterable):
if isinstance(matrix[0], Iterable):
prev_len = 0
for row in matrix:
if prev_len == 0:
prev_len = len(row)
result = True
else:
result = False
result = prev_len == len(row)
else:
result = True
else:
result = False
return result
def spiralPrint(a):
if checkMatrix(a) and len(a) > 0:
if check_matrix(a) and len(a) > 0:
matRow = len(a)
if type(a[0]) == list:
if isinstance(a[0], Iterable):
matCol = len(a[0])
else:
for dat in a:
@ -64,5 +63,6 @@ def spiralPrint(a):
# driver code
a = [[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12]]
spiralPrint(a)
if __name__ == "__main__":
a = ([1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12])
spiralPrint(a)