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print() is a function just like every other function (#1101)

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* print() is a function just like every other function
This commit is contained in:
Christian Clauss
2019-08-06 12:14:23 +02:00
committed by Harshil
parent 6654e1ec7d
commit 89acf5d017
13 changed files with 133 additions and 133 deletions
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12
data_structures/binary_tree/fenwick_tree.py
View File

@@ -16,14 +16,14 @@ class FenwickTree:
ret += self.ft[i]
i -= i & (-i)
return ret
if __name__ == '__main__':
f = FenwickTree(100)
f.update(1,20)
f.update(4,4)
print (f.query(1))
print (f.query(3))
print (f.query(4))
print(f.query(1))
print(f.query(3))
print(f.query(4))
f.update(2,-5)
print (f.query(1))
print (f.query(3))
print(f.query(1))
print(f.query(3))

18
data_structures/binary_tree/lazy_segment_tree.py
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@@ -2,13 +2,13 @@ from __future__ import print_function
import math
class SegmentTree:
def __init__(self, N):
self.N = N
self.st = [0 for i in range(0,4*N)] # approximate the overall size of segment tree with array N
self.lazy = [0 for i in range(0,4*N)] # create array to store lazy update
self.flag = [0 for i in range(0,4*N)] # flag for lazy update
def left(self, idx):
return idx*2
@@ -34,7 +34,7 @@ class SegmentTree:
self.lazy[self.right(idx)] = self.lazy[idx]
self.flag[self.left(idx)] = True
self.flag[self.right(idx)] = True
if r < a or l > b:
return True
if l >= a and r <= b :
@@ -74,18 +74,18 @@ class SegmentTree:
showList = []
for i in range(1,N+1):
showList += [self.query(1, 1, self.N, i, i)]
print (showList)
print(showList)
if __name__ == '__main__':
A = [1,2,-4,7,3,-5,6,11,-20,9,14,15,5,2,-8]
N = 15
segt = SegmentTree(N)
segt.build(1,1,N,A)
print (segt.query(1,1,N,4,6))
print (segt.query(1,1,N,7,11))
print (segt.query(1,1,N,7,12))
print(segt.query(1,1,N,4,6))
print(segt.query(1,1,N,7,11))
print(segt.query(1,1,N,7,12))
segt.update(1,1,N,1,3,111)
print (segt.query(1,1,N,1,15))
print(segt.query(1,1,N,1,15))
segt.update(1,1,N,7,8,235)
segt.showData()

20
data_structures/binary_tree/segment_tree.py
View File

@@ -2,12 +2,12 @@ from __future__ import print_function
import math
class SegmentTree:
def __init__(self, A):
self.N = len(A)
self.st = [0] * (4 * self.N) # approximate the overall size of segment tree with array N
self.build(1, 0, self.N - 1)
def left(self, idx):
return idx * 2
@@ -22,10 +22,10 @@ class SegmentTree:
self.build(self.left(idx), l, mid)
self.build(self.right(idx), mid + 1, r)
self.st[idx] = max(self.st[self.left(idx)] , self.st[self.right(idx)])
def update(self, a, b, val):
return self.update_recursive(1, 0, self.N - 1, a - 1, b - 1, val)
def update_recursive(self, idx, l, r, a, b, val): # update(1, 1, N, a, b, v) for update val v to [a,b]
if r < a or l > b:
return True
@@ -55,17 +55,17 @@ class SegmentTree:
showList = []
for i in range(1,N+1):
showList += [self.query(i, i)]
print (showList)
print(showList)
if __name__ == '__main__':
A = [1,2,-4,7,3,-5,6,11,-20,9,14,15,5,2,-8]
N = 15
segt = SegmentTree(A)
print (segt.query(4, 6))
print (segt.query(7, 11))
print (segt.query(7, 12))
print(segt.query(4, 6))
print(segt.query(7, 11))
print(segt.query(7, 12))
segt.update(1,3,111)
print (segt.query(1, 15))
print(segt.query(1, 15))
segt.update(7,8,235)
segt.showData()

42
data_structures/queue/double_ended_queue.py
View File

@@ -1,40 +1,40 @@
from __future__ import print_function
# Python code to demonstrate working of
# Python code to demonstrate working of
# extend(), extendleft(), rotate(), reverse()
# importing "collections" for deque operations
import collections
# initializing deque
de = collections.deque([1, 2, 3,])
# using extend() to add numbers to right end
# using extend() to add numbers to right end
# adds 4,5,6 to right end
de.extend([4,5,6])
# printing modified deque
print ("The deque after extending deque at end is : ")
print (de)
# using extendleft() to add numbers to left end
print("The deque after extending deque at end is : ")
print(de)
# using extendleft() to add numbers to left end
# adds 7,8,9 to right end
de.extendleft([7,8,9])
# printing modified deque
print ("The deque after extending deque at beginning is : ")
print (de)
print("The deque after extending deque at beginning is : ")
print(de)
# using rotate() to rotate the deque
# rotates by 3 to left
de.rotate(-3)
# printing modified deque
print ("The deque after rotating deque is : ")
print (de)
print("The deque after rotating deque is : ")
print(de)
# using reverse() to reverse the deque
de.reverse()
# printing modified deque
print ("The deque after reversing deque is : ")
print (de)
print("The deque after reversing deque is : ")
print(de)

92
data_structures/stacks/stock_span_problem.py
View File

@@ -1,52 +1,52 @@
'''
The stock span problem is a financial problem where we have a series of n daily
The stock span problem is a financial problem where we have a series of n daily
price quotes for a stock and we need to calculate span of stock's price for all n days.
The span Si of the stock's price on a given day i is defined as the maximum
number of consecutive days just before the given day, for which the price of the stock
The span Si of the stock's price on a given day i is defined as the maximum
number of consecutive days just before the given day, for which the price of the stock
on the current day is less than or equal to its price on the given day.
'''
from __future__ import print_function
def calculateSpan(price, S):
n = len(price)
# Create a stack and push index of fist element to it
st = []
st.append(0)
# Span value of first element is always 1
S[0] = 1
# Calculate span values for rest of the elements
for i in range(1, n):
# Pop elements from stack whlie stack is not
# empty and top of stack is smaller than price[i]
while( len(st) > 0 and price[st[0]] <= price[i]):
st.pop()
# If stack becomes empty, then price[i] is greater
# than all elements on left of it, i.e. price[0],
# price[1], ..price[i-1]. Else the price[i] is
# greater than elements after top of stack
S[i] = i+1 if len(st) <= 0 else (i - st[0])
# Push this element to stack
st.append(i)
# A utility function to print elements of array
def printArray(arr, n):
for i in range(0,n):
print (arr[i],end =" ")
# Driver program to test above function
price = [10, 4, 5, 90, 120, 80]
S = [0 for i in range(len(price)+1)]
# Fill the span values in array S[]
calculateSpan(price, S)
# Print the calculated span values
printArray(S, len(price))
def calculateSpan(price, S):
n = len(price)
# Create a stack and push index of fist element to it
st = []
st.append(0)
# Span value of first element is always 1
S[0] = 1
# Calculate span values for rest of the elements
for i in range(1, n):
# Pop elements from stack whlie stack is not
# empty and top of stack is smaller than price[i]
while( len(st) > 0 and price[st[0]] <= price[i]):
st.pop()
# If stack becomes empty, then price[i] is greater
# than all elements on left of it, i.e. price[0],
# price[1], ..price[i-1]. Else the price[i] is
# greater than elements after top of stack
S[i] = i+1 if len(st) <= 0 else (i - st[0])
# Push this element to stack
st.append(i)
# A utility function to print elements of array
def printArray(arr, n):
for i in range(0,n):
print(arr[i],end =" ")
# Driver program to test above function
price = [10, 4, 5, 90, 120, 80]
S = [0 for i in range(len(price)+1)]
# Fill the span values in array S[]
calculateSpan(price, S)
# Print the calculated span values
printArray(S, len(price))