algorithm/Python
1
0
Fork 0
mirror of https://github.com/TheAlgorithms/Python.git synced 2025-07-27 10:22:36 +08:00
Code Issues Packages Projects Releases Wiki Activity

increment 1

Browse Source
This commit is contained in:
Alex Brown
2018-10-19 07:48:28 -05:00
parent 718b99ae39
commit 564179a0ec
131 changed files with 16252 additions and 0 deletions
Download Patch File Download Diff File Expand all files Collapse all files

20
project_euler/Problem 06/sol1.py Normal file
View File

@ -0,0 +1,20 @@
# -*- coding: utf-8 -*-
'''
Problem:
The sum of the squares of the first ten natural numbers is,
1^2 + 2^2 + ... + 10^2 = 385
The square of the sum of the first ten natural numbers is,
(1 + 2 + ... + 10)^2 = 552 = 3025
Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 − 385 = 2640.
Find the difference between the sum of the squares of the first N natural numbers and the square of the sum.
'''
from __future__ import print_function
suma = 0
sumb = 0
n = int(raw_input())
for i in range(1,n+1):
suma += i**2
sumb += i
sum = sumb**2 - suma
print(sum)

16
project_euler/Problem 06/sol2.py Normal file
View File

@ -0,0 +1,16 @@
# -*- coding: utf-8 -*-
'''
Problem:
The sum of the squares of the first ten natural numbers is,
1^2 + 2^2 + ... + 10^2 = 385
The square of the sum of the first ten natural numbers is,
(1 + 2 + ... + 10)^2 = 552 = 3025
Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 − 385 = 2640.
Find the difference between the sum of the squares of the first N natural numbers and the square of the sum.
'''
from __future__ import print_function
n = int(raw_input())
suma = n*(n+1)/2
suma **= 2
sumb = n*(n+1)*(2*n+1)/6
print(suma-sumb)