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This commit is contained in:
Alex Brown
2018-10-19 07:48:28 -05:00
parent 718b99ae39
commit 564179a0ec
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'''
The stock span problem is a financial problem where we have a series of n daily
price quotes for a stock and we need to calculate span of stock's price for all n days.
The span Si of the stock's price on a given day i is defined as the maximum
number of consecutive days just before the given day, for which the price of the stock
on the current day is less than or equal to its price on the given day.
'''
from __future__ import print_function
def calculateSpan(price, S):
n = len(price)
# Create a stack and push index of fist element to it
st = []
st.append(0)
# Span value of first element is always 1
S[0] = 1
# Calculate span values for rest of the elements
for i in range(1, n):
# Pop elements from stack whlie stack is not
# empty and top of stack is smaller than price[i]
while( len(st) > 0 and price[st[0]] <= price[i]):
st.pop()
# If stack becomes empty, then price[i] is greater
# than all elements on left of it, i.e. price[0],
# price[1], ..price[i-1]. Else the price[i] is
# greater than elements after top of stack
S[i] = i+1 if len(st) <= 0 else (i - st[0])
# Push this element to stack
st.append(i)
# A utility function to print elements of array
def printArray(arr, n):
for i in range(0,n):
print (arr[i],end =" ")
# Driver program to test above function
price = [10, 4, 5, 90, 120, 80]
S = [0 for i in range(len(price)+1)]
# Fill the span values in array S[]
calculateSpan(price, S)
# Print the calculated span values
printArray(S, len(price))

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class Stack:
def __init__(self):
self.stack = []
self.top = 0
def is_empty(self):
return (self.top == 0)
def push(self, item):
if self.top < len(self.stack):
self.stack[self.top] = item
else:
self.stack.append(item)
self.top += 1
def pop(self):
if self.is_empty():
return None
else:
self.top -= 1
return self.stack[self.top]

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from __future__ import print_function
from __future__ import absolute_import
from .Stack import Stack
__author__ = 'Omkar Pathak'
def balanced_parentheses(parentheses):
""" Use a stack to check if a string of parentheses are balanced."""
stack = Stack(len(parentheses))
for parenthesis in parentheses:
if parenthesis == '(':
stack.push(parenthesis)
elif parenthesis == ')':
stack.pop()
return not stack.is_empty()
if __name__ == '__main__':
examples = ['((()))', '((())']
print('Balanced parentheses demonstration:\n')
for example in examples:
print(example + ': ' + str(balanced_parentheses(example)))

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from __future__ import print_function
from __future__ import absolute_import
import string
from .Stack import Stack
__author__ = 'Omkar Pathak'
def is_operand(char):
return char in string.ascii_letters or char in string.digits
def precedence(char):
""" Return integer value representing an operator's precedence, or
order of operation.
https://en.wikipedia.org/wiki/Order_of_operations
"""
dictionary = {'+': 1, '-': 1,
'*': 2, '/': 2,
'^': 3}
return dictionary.get(char, -1)
def infix_to_postfix(expression):
""" Convert infix notation to postfix notation using the Shunting-yard
algorithm.
https://en.wikipedia.org/wiki/Shunting-yard_algorithm
https://en.wikipedia.org/wiki/Infix_notation
https://en.wikipedia.org/wiki/Reverse_Polish_notation
"""
stack = Stack(len(expression))
postfix = []
for char in expression:
if is_operand(char):
postfix.append(char)
elif char not in {'(', ')'}:
while (not stack.is_empty()
and precedence(char) <= precedence(stack.peek())):
postfix.append(stack.pop())
stack.push(char)
elif char == '(':
stack.push(char)
elif char == ')':
while not stack.is_empty() and stack.peek() != '(':
postfix.append(stack.pop())
# Pop '(' from stack. If there is no '(', there is a mismatched
# parentheses.
if stack.peek() != '(':
raise ValueError('Mismatched parentheses')
stack.pop()
while not stack.is_empty():
postfix.append(stack.pop())
return ' '.join(postfix)
if __name__ == '__main__':
expression = 'a+b*(c^d-e)^(f+g*h)-i'
print('Infix to Postfix Notation demonstration:\n')
print('Infix notation: ' + expression)
print('Postfix notation: ' + infix_to_postfix(expression))

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from __future__ import print_function
# Function to print element and NGE pair for all elements of list
def printNGE(arr):
for i in range(0, len(arr), 1):
next = -1
for j in range(i+1, len(arr), 1):
if arr[i] < arr[j]:
next = arr[j]
break
print(str(arr[i]) + " -- " + str(next))
# Driver program to test above function
arr = [11,13,21,3]
printNGE(arr)

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from __future__ import print_function
__author__ = 'Omkar Pathak'
class Stack(object):
""" A stack is an abstract data type that serves as a collection of
elements with two principal operations: push() and pop(). push() adds an
element to the top of the stack, and pop() removes an element from the top
of a stack. The order in which elements come off of a stack are
Last In, First Out (LIFO).
https://en.wikipedia.org/wiki/Stack_(abstract_data_type)
"""
def __init__(self, limit=10):
self.stack = []
self.limit = limit
def __bool__(self):
return not bool(self.stack)
def __str__(self):
return str(self.stack)
def push(self, data):
""" Push an element to the top of the stack."""
if len(self.stack) >= self.limit:
raise StackOverflowError
self.stack.append(data)
def pop(self):
""" Pop an element off of the top of the stack."""
if self.stack:
return self.stack.pop()
else:
raise IndexError('pop from an empty stack')
def peek(self):
""" Peek at the top-most element of the stack."""
if self.stack:
return self.stack[-1]
def is_empty(self):
""" Check if a stack is empty."""
return not bool(self.stack)
def size(self):
""" Return the size of the stack."""
return len(self.stack)
class StackOverflowError(BaseException):
pass
if __name__ == '__main__':
stack = Stack()
for i in range(10):
stack.push(i)
print('Stack demonstration:\n')
print('Initial stack: ' + str(stack))
print('pop(): ' + str(stack.pop()))
print('After pop(), the stack is now: ' + str(stack))
print('peek(): ' + str(stack.peek()))
stack.push(100)
print('After push(100), the stack is now: ' + str(stack))
print('is_empty(): ' + str(stack.is_empty()))
print('size(): ' + str(stack.size()))