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Modernize Python 2 code to get ready for Python 3
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@ -7,6 +7,11 @@ Find the sum of all the multiples of 3 or 5 below N.
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'''
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This solution is based on the pattern that the successive numbers in the series follow: 0+3,+2,+1,+3,+1,+2,+3.
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'''
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from __future__ import print_function
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try:
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raw_input # Python 2
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except NameError:
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raw_input = input # Python 3
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n = int(raw_input().strip())
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sum=0;
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num=0;
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@ -39,4 +44,4 @@ while(1):
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if(num>=n):
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break
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sum+=num
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print sum;
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print(sum);
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