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Simplify code by dropping support for legacy Python (#1143)
* Simplify code by dropping support for legacy Python * sort() --> sorted()
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@ -4,17 +4,11 @@ If we list all the natural numbers below 10 that are multiples of 3 or 5,
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we get 3,5,6 and 9. The sum of these multiples is 23.
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Find the sum of all the multiples of 3 or 5 below N.
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"""
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from __future__ import print_function
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try:
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raw_input # Python 2
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except NameError:
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raw_input = input # Python 3
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def solution(n):
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"""Returns the sum of all the multiples of 3 or 5 below n.
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>>> solution(3)
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0
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>>> solution(4)
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@ -36,4 +30,4 @@ def solution(n):
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if __name__ == "__main__":
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print(solution(int(raw_input().strip())))
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print(solution(int(input().strip())))
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