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Added doctest and more explanation about Dijkstra execution. (#1014)
* Added doctest and more explanation about Dijkstra execution. * tests were not passing with python2 due to missing __init__.py file at number_theory folder * Removed the dot at the beginning of the imported modules names because 'python3 -m doctest -v data_structures/hashing/*.py' and 'python3 -m doctest -v data_structures/stacks/*.py' were failing not finding hash_table.py and stack.py modules. * Moved global code to main scope and added doctest for project euler problems 1 to 14. * Added test case for negative input. * Changed N variable to do not use end of line scape because in case there is a space after it the script will break making it much more error prone. * Added problems description and doctests to the ones that were missing. Limited line length to 79 and executed python black over all scripts. * Changed the way files are loaded to support pytest call. * Added __init__.py to problems to make them modules and allow pytest execution. * Added project_euler folder to test units execution * Changed 'os.path.split(os.path.realpath(__file__))' to 'os.path.dirname()'
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committed by
cclauss

parent
2fb3beeaf1
commit
267b5eff40
@ -1,15 +1,36 @@
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from __future__ import print_function
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# Program to find the product of a,b,c which are Pythagorean Triplet that satisfice the following:
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# 1. a < b < c
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# 2. a**2 + b**2 = c**2
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# 3. a + b + c = 1000
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"""
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Problem Statement:
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A Pythagorean triplet is a set of three natural numbers, a < b < c, for which,
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a^2 + b^2 = c^2
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For example, 3^2 + 4^2 = 9 + 16 = 25 = 5^2.
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print("Please Wait...")
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for a in range(300):
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for b in range(400):
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for c in range(500):
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if(a < b < c):
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if((a**2) + (b**2) == (c**2)):
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if((a+b+c) == 1000):
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print(("Product of",a,"*",b,"*",c,"=",(a*b*c)))
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break
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There exists exactly one Pythagorean triplet for which a + b + c = 1000.
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Find the product abc.
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"""
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from __future__ import print_function
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def solution():
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"""
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Returns the product of a,b,c which are Pythagorean Triplet that satisfies
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the following:
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1. a < b < c
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2. a**2 + b**2 = c**2
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3. a + b + c = 1000
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>>> solution()
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31875000
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"""
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for a in range(300):
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for b in range(400):
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for c in range(500):
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if a < b < c:
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if (a ** 2) + (b ** 2) == (c ** 2):
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if (a + b + c) == 1000:
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return a * b * c
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break
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if __name__ == "__main__":
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print("Please Wait...")
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print(solution())
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