Added doctest and more explanation about Dijkstra execution. (#1014)

* Added doctest and more explanation about Dijkstra execution.

* tests were not passing with python2 due to missing __init__.py file at number_theory folder

* Removed the dot at the beginning of the imported modules names because 'python3 -m doctest -v data_structures/hashing/*.py' and 'python3 -m doctest -v data_structures/stacks/*.py' were failing not finding hash_table.py and stack.py modules.

* Moved global code to main scope and added doctest for project euler problems 1 to 14.

* Added test case for negative input.

* Changed N variable to do not use end of line scape because in case there is a space after it the script will break making it much more error prone.

* Added problems description and doctests to the ones that were missing. Limited line length to 79 and executed python black over all scripts.

* Changed the way files are loaded to support pytest call.

* Added __init__.py to problems to make them modules and allow pytest execution.

* Added project_euler folder to test units execution

* Changed 'os.path.split(os.path.realpath(__file__))' to 'os.path.dirname()'
This commit is contained in:
Bruno Simas Hadlich
2019-07-16 20:09:53 -03:00
committed by cclauss
parent 2fb3beeaf1
commit 267b5eff40
100 changed files with 2621 additions and 1438 deletions

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@ -1,29 +1,50 @@
'''
"""
Problem:
A palindromic number reads the same both ways. The largest palindrome made from the product of two 2-digit numbers is 9009 = 91 x 99.
Find the largest palindrome made from the product of two 3-digit numbers which is less than N.
'''
A palindromic number reads the same both ways. The largest palindrome made from
the product of two 2-digit numbers is 9009 = 91 x 99.
Find the largest palindrome made from the product of two 3-digit numbers which
is less than N.
"""
from __future__ import print_function
limit = int(input("limit? "))
# fetchs the next number
for number in range(limit-1,10000,-1):
try:
raw_input # Python 2
except NameError:
raw_input = input # Python 3
# converts number into string.
strNumber = str(number)
# checks whether 'strNumber' is a palindrome.
if(strNumber == strNumber[::-1]):
def solution(n):
"""Returns the largest palindrome made from the product of two 3-digit
numbers which is less than n.
>>> solution(20000)
19591
>>> solution(30000)
29992
>>> solution(40000)
39893
"""
# fetchs the next number
for number in range(n - 1, 10000, -1):
divisor = 999
# converts number into string.
strNumber = str(number)
# if 'number' is a product of two 3-digit numbers
# then number is the answer otherwise fetch next number.
while(divisor != 99):
if((number % divisor == 0) and (len(str(number / divisor)) == 3)):
# checks whether 'strNumber' is a palindrome.
if strNumber == strNumber[::-1]:
print(number)
exit(0)
divisor = 999
divisor -=1
# if 'number' is a product of two 3-digit numbers
# then number is the answer otherwise fetch next number.
while divisor != 99:
if (number % divisor == 0) and (
len(str(int(number / divisor))) == 3
):
return number
divisor -= 1
if __name__ == "__main__":
print(solution(int(raw_input().strip())))

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@ -1,17 +1,38 @@
'''
"""
Problem:
A palindromic number reads the same both ways. The largest palindrome made from the product of two 2-digit numbers is 9009 = 91 x 99.
Find the largest palindrome made from the product of two 3-digit numbers which is less than N.
'''
A palindromic number reads the same both ways. The largest palindrome made from
the product of two 2-digit numbers is 9009 = 91 x 99.
Find the largest palindrome made from the product of two 3-digit numbers which
is less than N.
"""
from __future__ import print_function
n = int(input().strip())
answer = 0
for i in range(999,99,-1): #3 digit nimbers range from 999 down to 100
for j in range(999,99,-1):
t = str(i*j)
if t == t[::-1] and i*j < n:
answer = max(answer,i*j)
print(answer)
exit(0)
try:
raw_input # Python 2
except NameError:
raw_input = input # Python 3
def solution(n):
"""Returns the largest palindrome made from the product of two 3-digit
numbers which is less than n.
>>> solution(20000)
19591
>>> solution(30000)
29992
>>> solution(40000)
39893
"""
answer = 0
for i in range(999, 99, -1): # 3 digit nimbers range from 999 down to 100
for j in range(999, 99, -1):
t = str(i * j)
if t == t[::-1] and i * j < n:
answer = max(answer, i * j)
return answer
if __name__ == "__main__":
print(solution(int(raw_input().strip())))