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Project Euler Solution Added
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@ -42,3 +42,10 @@ PROBLEMS:
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a^2 + b^2 = c^2
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There exists exactly one Pythagorean triplet for which a + b + c = 1000.
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Find the product abc.
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14. The following iterative sequence is defined for the set of positive integers:
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n → n/2 (n is even)
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n → 3n + 1 (n is odd)
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Using the rule above and starting with 13, we generate the following sequence:
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13 → 40 → 20 → 10 → 5 → 16 → 8 → 4 → 2 → 1
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Which starting number, under one million, produces the longest chain?
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