Files
LeetCode-Go/structures/TreeNode.go
2020-08-07 10:12:09 +08:00

234 lines
4.2 KiB
Go

package structures
import (
"fmt"
)
// TreeNode is tree's node
type TreeNode struct {
Val int
Left *TreeNode
Right *TreeNode
}
// NULL 方便添加测试数据
var NULL = -1 << 63
// Ints2TreeNode 利用 []int 生成 *TreeNode
func Ints2TreeNode(ints []int) *TreeNode {
n := len(ints)
if n == 0 {
return nil
}
root := &TreeNode{
Val: ints[0],
}
queue := make([]*TreeNode, 1, n*2)
queue[0] = root
i := 1
for i < n {
node := queue[0]
queue = queue[1:]
if i < n && ints[i] != NULL {
node.Left = &TreeNode{Val: ints[i]}
queue = append(queue, node.Left)
}
i++
if i < n && ints[i] != NULL {
node.Right = &TreeNode{Val: ints[i]}
queue = append(queue, node.Right)
}
i++
}
return root
}
// GetTargetNode 返回 Val = target 的 TreeNode
// root 中一定有 node.Val = target
func GetTargetNode(root *TreeNode, target int) *TreeNode {
if root == nil || root.Val == target {
return root
}
res := GetTargetNode(root.Left, target)
if res != nil {
return res
}
return GetTargetNode(root.Right, target)
}
func indexOf(val int, nums []int) int {
for i, v := range nums {
if v == val {
return i
}
}
msg := fmt.Sprintf("%d 不存在于 %v 中", val, nums)
panic(msg)
}
// PreIn2Tree 把 preorder 和 inorder 切片转换成 二叉树
func PreIn2Tree(pre, in []int) *TreeNode {
if len(pre) != len(in) {
panic("preIn2Tree 中两个切片的长度不相等")
}
if len(in) == 0 {
return nil
}
res := &TreeNode{
Val: pre[0],
}
if len(in) == 1 {
return res
}
idx := indexOf(res.Val, in)
res.Left = PreIn2Tree(pre[1:idx+1], in[:idx])
res.Right = PreIn2Tree(pre[idx+1:], in[idx+1:])
return res
}
// InPost2Tree 把 inorder 和 postorder 切片转换成 二叉树
func InPost2Tree(in, post []int) *TreeNode {
if len(post) != len(in) {
panic("inPost2Tree 中两个切片的长度不相等")
}
if len(in) == 0 {
return nil
}
res := &TreeNode{
Val: post[len(post)-1],
}
if len(in) == 1 {
return res
}
idx := indexOf(res.Val, in)
res.Left = InPost2Tree(in[:idx], post[:idx])
res.Right = InPost2Tree(in[idx+1:], post[idx:len(post)-1])
return res
}
// Tree2Preorder 把 二叉树 转换成 preorder 的切片
func Tree2Preorder(root *TreeNode) []int {
if root == nil {
return nil
}
if root.Left == nil && root.Right == nil {
return []int{root.Val}
}
res := []int{root.Val}
res = append(res, Tree2Preorder(root.Left)...)
res = append(res, Tree2Preorder(root.Right)...)
return res
}
// Tree2Inorder 把 二叉树转换成 inorder 的切片
func Tree2Inorder(root *TreeNode) []int {
if root == nil {
return nil
}
if root.Left == nil && root.Right == nil {
return []int{root.Val}
}
res := Tree2Inorder(root.Left)
res = append(res, root.Val)
res = append(res, Tree2Inorder(root.Right)...)
return res
}
// Tree2Postorder 把 二叉树 转换成 postorder 的切片
func Tree2Postorder(root *TreeNode) []int {
if root == nil {
return nil
}
if root.Left == nil && root.Right == nil {
return []int{root.Val}
}
res := Tree2Postorder(root.Left)
res = append(res, Tree2Postorder(root.Right)...)
res = append(res, root.Val)
return res
}
// Equal return ture if tn == a
func (tn *TreeNode) Equal(a *TreeNode) bool {
if tn == nil && a == nil {
return true
}
if tn == nil || a == nil || tn.Val != a.Val {
return false
}
return tn.Left.Equal(a.Left) && tn.Right.Equal(a.Right)
}
// Tree2ints 把 *TreeNode 按照行还原成 []int
func Tree2ints(tn *TreeNode) []int {
res := make([]int, 0, 1024)
queue := []*TreeNode{tn}
for len(queue) > 0 {
size := len(queue)
for i := 0; i < size; i++ {
nd := queue[i]
if nd == nil {
res = append(res, NULL)
} else {
res = append(res, nd.Val)
queue = append(queue, nd.Left, nd.Right)
}
}
queue = queue[size:]
}
i := len(res)
for i > 0 && res[i-1] == NULL {
i--
}
return res[:i]
}
// T2s convert *TreeNode to []int
func T2s(head *TreeNode, array *[]int) {
fmt.Printf("运行到这里了 head = %v array = %v\n", head, array)
// fmt.Printf("****array = %v\n", array)
// fmt.Printf("****head = %v\n", head.Val)
*array = append(*array, head.Val)
if head.Left != nil {
T2s(head.Left, array)
}
if head.Right != nil {
T2s(head.Right, array)
}
}