# [71. Simplify Path](https://leetcode.com/problems/simplify-path/) ## 题目 Given an absolute path for a file (Unix-style), simplify it. Or in other words, convert it to the canonical path. In a UNIX-style file system, a period . refers to the current directory. Furthermore, a double period .. moves the directory up a level. For more information, see: Absolute path vs relative path in Linux/Unix Note that the returned canonical path must always begin with a slash /, and there must be only a single slash / between two directory names. The last directory name (if it exists) must not end with a trailing /. Also, the canonical path must be the shortest string representing the absolute path. **Example 1**: ``` Input: "/home/" Output: "/home" Explanation: Note that there is no trailing slash after the last directory name. ``` **Example 2**: ``` Input: "/../" Output: "/" Explanation: Going one level up from the root directory is a no-op, as the root level is the highest level you can go. ``` **Example 3**: ``` Input: "/home//foo/" Output: "/home/foo" Explanation: In the canonical path, multiple consecutive slashes are replaced by a single one. ``` **Example 4**: ``` Input: "/a/./b/../../c/" Output: "/c" ``` **Example 5**: ``` Input: "/a/../../b/../c//.//" Output: "/c" ``` **Example 6**: ``` Input: "/a//b////c/d//././/.." Output: "/a/b/c" ``` ## 题目大意 给出一个 Unix 的文件路径,要求简化这个路径。这道题也是考察栈的题目。 ## 解题思路 这道题笔者提交了好多次才通过,并不是题目难,而是边界条件很多,没考虑全一种情况就会出错。有哪些边界情况就看笔者的 test 文件吧。 ## 代码 ```go package leetcode import ( "path/filepath" "strings" ) // 解法一 func simplifyPath(path string) string { arr := strings.Split(path, "/") stack := make([]string, 0) var res string for i := 0; i < len(arr); i++ { cur := arr[i] //cur := strings.TrimSpace(arr[i]) 更加严谨的做法应该还要去掉末尾的空格 if cur == ".." { if len(stack) > 0 { stack = stack[:len(stack)-1] } } else if cur != "." && len(cur) > 0 { stack = append(stack, arr[i]) } } if len(stack) == 0 { return "/" } res = strings.Join(stack, "/") return "/" + res } // 解法二 golang 的官方库 API func simplifyPath1(path string) string { return filepath.Clean(path) } ```