# [232. Implement Queue using Stacks](https://leetcode.com/problems/implement-queue-using-stacks/) ## 题目 Implement the following operations of a queue using stacks. - push(x) -- Push element x to the back of queue. - pop() -- Removes the element from in front of queue. - peek() -- Get the front element. - empty() -- Return whether the queue is empty. **Example**: ``` MyQueue queue = new MyQueue(); queue.push(1); queue.push(2); queue.peek(); // returns 1 queue.pop(); // returns 1 queue.empty(); // returns false ``` **Note**: - You must use only standard operations of a stack -- which means only push to top, peek/pop from top, size, and is empty operations are valid. - Depending on your language, stack may not be supported natively. You may simulate a stack by using a list or deque (double-ended queue), as long as you use only standard operations of a stack. - You may assume that all operations are valid (for example, no pop or peek operations will be called on an empty queue). ## 题目大意 题目要求用栈实现一个队列的基本操作:push(x)、pop()、peek()、empty()。 ## 解题思路 按照题目要求实现即可。 ## 代码 ```go package leetcode type MyQueue struct { Stack *[]int Queue *[]int } /** Initialize your data structure here. */ func Constructor232() MyQueue { tmp1, tmp2 := []int{}, []int{} return MyQueue{Stack: &tmp1, Queue: &tmp2} } /** Push element x to the back of queue. */ func (this *MyQueue) Push(x int) { *this.Stack = append(*this.Stack, x) } /** Removes the element from in front of queue and returns that element. */ func (this *MyQueue) Pop() int { if len(*this.Queue) == 0 { this.fromStackToQueue(this.Stack, this.Queue) } popped := (*this.Queue)[len(*this.Queue)-1] *this.Queue = (*this.Queue)[:len(*this.Queue)-1] return popped } /** Get the front element. */ func (this *MyQueue) Peek() int { if len(*this.Queue) == 0 { this.fromStackToQueue(this.Stack, this.Queue) } return (*this.Queue)[len(*this.Queue)-1] } /** Returns whether the queue is empty. */ func (this *MyQueue) Empty() bool { return len(*this.Stack)+len(*this.Queue) == 0 } func (this *MyQueue) fromStackToQueue(s, q *[]int) { for len(*s) > 0 { popped := (*s)[len(*s)-1] *s = (*s)[:len(*s)-1] *q = append(*q, popped) } } ```