mirror of
https://github.com/halfrost/LeetCode-Go.git
synced 2025-07-07 01:44:56 +08:00
add: leetcode 1446 readme
This commit is contained in:
76
leetcode/1446.Consecutive-Characters/README.md
Normal file
76
leetcode/1446.Consecutive-Characters/README.md
Normal file
@ -0,0 +1,76 @@
|
|||||||
|
# [1446. Consecutive Characters](https://leetcode-cn.com/problems/consecutive-characters/)
|
||||||
|
|
||||||
|
## 题目
|
||||||
|
|
||||||
|
The power of the string is the maximum length of a non-empty substring that contains only one unique character.
|
||||||
|
|
||||||
|
Given a string s, return the power of s.
|
||||||
|
|
||||||
|
**Example 1**:
|
||||||
|
|
||||||
|
Input: s = "leetcode"
|
||||||
|
Output: 2
|
||||||
|
Explanation: The substring "ee" is of length 2 with the character 'e' only.
|
||||||
|
|
||||||
|
**Example 2**:
|
||||||
|
|
||||||
|
Input: s = "abbcccddddeeeeedcba"
|
||||||
|
Output: 5
|
||||||
|
Explanation: The substring "eeeee" is of length 5 with the character 'e' only.
|
||||||
|
|
||||||
|
**Example 3**:
|
||||||
|
|
||||||
|
Input: s = "triplepillooooow"
|
||||||
|
Output: 5
|
||||||
|
|
||||||
|
**Example 4**:
|
||||||
|
|
||||||
|
Input: s = "hooraaaaaaaaaaay"
|
||||||
|
Output: 11
|
||||||
|
|
||||||
|
**Example 5**:
|
||||||
|
|
||||||
|
Input: s = "tourist"
|
||||||
|
Output: 1
|
||||||
|
|
||||||
|
**Constraints:**
|
||||||
|
|
||||||
|
- 1 <= s.length <= 500
|
||||||
|
- s consists of only lowercase English letters.
|
||||||
|
|
||||||
|
## 题目大意
|
||||||
|
|
||||||
|
给你一个字符串 s ,字符串的「能量」定义为:只包含一种字符的最长非空子字符串的长度。
|
||||||
|
|
||||||
|
请你返回字符串的能量。
|
||||||
|
|
||||||
|
## 解题思路
|
||||||
|
|
||||||
|
- 顺序遍历进行统计
|
||||||
|
|
||||||
|
## 代码
|
||||||
|
|
||||||
|
```go
|
||||||
|
package leetcode
|
||||||
|
|
||||||
|
func maxPower(s string) int {
|
||||||
|
cur := s[0]
|
||||||
|
cnt := 1
|
||||||
|
ans := 1
|
||||||
|
for i := 1; i < len(s); i++ {
|
||||||
|
if cur == s[i] {
|
||||||
|
cnt++
|
||||||
|
} else {
|
||||||
|
if cnt > ans {
|
||||||
|
ans = cnt
|
||||||
|
}
|
||||||
|
cur = s[i]
|
||||||
|
cnt = 1
|
||||||
|
}
|
||||||
|
}
|
||||||
|
if cnt > ans {
|
||||||
|
ans = cnt
|
||||||
|
}
|
||||||
|
return ans
|
||||||
|
}
|
||||||
|
```
|
Reference in New Issue
Block a user