添加 problem 223

Algorithms/0223. Rectangle Area/223. Rectangle Area.go

@@ -0,0 +1,14 @@
+package leetcode
+
+func computeArea(A int, B int, C int, D int, E int, F int, G int, H int) int {
+	X0, Y0, X1, Y1 := max(A, E), max(B, F), min(C, G), min(D, H)
+	return area(A, B, C, D) + area(E, F, G, H) - area(X0, Y0, X1, Y1)
+}
+
+func area(x0, y0, x1, y1 int) int {
+	l, h := x1-x0, y1-y0
+	if l <= 0 || h <= 0 {
+		return 0
+	}
+	return l * h
+}

Algorithms/0223. Rectangle Area/223. Rectangle Area_test.go

@@ -0,0 +1,49 @@
+package leetcode
+
+import (
+	"fmt"
+	"testing"
+)
+
+type question223 struct {
+	para223
+	ans223
+}
+
+// para 是参数
+// one 代表第一个参数
+type para223 struct {
+	A int
+	B int
+	C int
+	D int
+	E int
+	F int
+	G int
+	H int
+}
+
+// ans 是答案
+// one 代表第一个答案
+type ans223 struct {
+	one int
+}
+
+func Test_Problem223(t *testing.T) {
+
+	qs := []question223{
+
+		question223{
+			para223{-3, 0, 3, 4, 0, -1, 9, 2},
+			ans223{45},
+		},
+	}
+
+	fmt.Printf("------------------------Leetcode Problem 223------------------------\n")
+
+	for _, q := range qs {
+		_, p := q.ans223, q.para223
+		fmt.Printf("【input】:%v       【output】:%v\n", p, computeArea(p.A, p.B, p.C, p.D, p.E, p.F, p.G, p.H))
+	}
+	fmt.Printf("\n\n\n")
+}

Algorithms/0223. Rectangle Area/README.md

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+# [223. Rectangle Area](https://leetcode.com/problems/rectangle-area/)
+
+
+## 题目:
+
+Find the total area covered by two **rectilinear** rectangles in a **2D** plane.
+
+Each rectangle is defined by its bottom left corner and top right corner as shown in the figure.
+
+![](https://assets.leetcode-cn.com/aliyun-lc-upload/uploads/2018/10/22/rectangle_area.png)
+
+**Example:**
+
+    Input: A = -3, B = 0, C = 3, D = 4, E = 0, F = -1, G = 9, H = 2
+    Output: 45
+
+**Note:**
+
+Assume that the total area is never beyond the maximum possible value of **int**.
+
+
+
+## 题目大意
+
+在二维平面上计算出两个由直线构成的矩形重叠后形成的总面积。每个矩形由其左下顶点和右上顶点坐标表示，如图所示。说明: 假设矩形面积不会超出 int 的范围。
+
+## 解题思路
+
+
+- 给出两个矩形的坐标，求这两个矩形在坐标轴上覆盖的总面积。
+- 几何题，由于只有 2 个矩形，所以按照题意做即可。先分别求两个矩形的面积，加起来再减去两个矩形重叠的面积。