Add solution 1668、1669、1670、1672、1673

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# [1668. Maximum Repeating Substring](https://leetcode.com/problems/maximum-repeating-substring/)
## 题目
For a string `sequence`, a string `word` is **`k`-repeating** if `word` concatenated `k` times is a substring of `sequence`. The `word`'s **maximum `k`-repeating value** is the highest value `k` where `word` is `k`-repeating in `sequence`. If `word` is not a substring of `sequence`, `word`'s maximum `k`-repeating value is `0`.
Given strings `sequence` and `word`, return *the **maximum `k`-repeating value** of `word` in `sequence`*.
**Example 1:**
```
Input: sequence = "ababc", word = "ab"
Output: 2
Explanation: "abab" is a substring in "ababc".
```
**Example 2:**
```
Input: sequence = "ababc", word = "ba"
Output: 1
Explanation: "ba" is a substring in "ababc". "baba" is not a substring in "ababc".
```
**Example 3:**
```
Input: sequence = "ababc", word = "ac"
Output: 0
Explanation: "ac" is not a substring in "ababc".
```
**Constraints:**
- `1 <= sequence.length <= 100`
- `1 <= word.length <= 100`
- `sequence` and `word` contains only lowercase English letters.
## 题目大意
给你一个字符串 sequence ,如果字符串 word 连续重复 k 次形成的字符串是 sequence 的一个子字符串,那么单词 word 的 重复值为 k 。单词 word 的 最大重复值 是单词 word 在 sequence 中最大的重复值。如果 word 不是 sequence 的子串,那么重复值 k 为 0 。给你一个字符串 sequence 和 word ,请你返回 最大重复值 k 。
## 解题思路
- 循环叠加构造 `word`,每次构造出新的 `word` 都在 `sequence` 查找一次,如果找到就输出叠加次数,否则继续叠加构造,直到字符串长度和 `sequence` 一样长,最终都没有找到则输出 0 。
## 代码
```go
package leetcode
import (
"strings"
)
func maxRepeating(sequence string, word string) int {
for i := len(sequence) / len(word); i >= 0; i-- {
tmp := ""
for j := 0; j < i; j++ {
tmp += word
}
if strings.Contains(sequence, tmp) {
return i
}
}
return 0
}
```