Add solution 0494

leetcode/0495.Teemo-Attacking/README.md

@@ -1,4 +1,4 @@
-# [495. Teemo Attacking](https://leetcode-cn.com/problems/teemo-attacking/)
+# [495. Teemo Attacking](https://leetcode.com/problems/teemo-attacking/)
 
 
 ## 题目
@@ -55,15 +55,16 @@ Ashe is poisoned for seconds 1, 2, and 3, which is 3 seconds in total.
 
 ## 解题思路
 
-- i从1开始计数，令t等于timeSeries[i - 1]
-- 比较end(t + duration - 1)和timeSeries[i]的大小，
-  - 如果end小于timeSeries[i],ans+=duration
-  - 否则ans += timeSeries[i] - t
-- ans += duration并返回ans
+- i 从 1 开始计数，令 t 等于 timeSeries[i - 1]
+- 比较 end(t + duration - 1) 和 timeSeries[i] 的大小，
+  - 如果 end 小于 timeSeries[i],ans+=duration
+  - 否则 ans += timeSeries[i] - t
+- ans += duration 并返回 ans
 
 ## 代码
 
 ```go
+
 package leetcode
 
 func findPoisonedDuration(timeSeries []int, duration int) int {
@@ -80,4 +81,5 @@ func findPoisonedDuration(timeSeries []int, duration int) int {
 	ans += duration
 	return ans
 }
+
 ```