Update solution 0065

leetcode/0065.Valid-Number/65. Valid Number.go

@@ -2,7 +2,6 @@ package leetcode
 
 func isNumber(s string) bool {
 	numFlag, dotFlag, eFlag := false, false, false
-
 	for i := 0; i < len(s); i++ {
 		if '0' <= s[i] && s[i] <= '9' {
 			numFlag = true

leetcode/0065.Valid-Number/README.md

@@ -47,3 +47,32 @@ Given a string s, return true if s is a **valid number.**
     - 如果是 'e/E', 则需要 'e/E'没有出现过，并且前面出现过数字，才会进行标记
     - 如果是 '+/-', 则需要是第一个字符，或者前一个字符是 'e/E'，才会进行标记，并重置数字出现的标识
     - 最后返回时，需要字符串中至少出现过数字，避免下列case: s == '.' or 'e/E' or '+/e' and etc...
+
+## 代码
+
+```go
+
+package leetcode
+
+func isNumber(s string) bool {
+	numFlag, dotFlag, eFlag := false, false, false
+	for i := 0; i < len(s); i++ {
+		if '0' <= s[i] && s[i] <= '9' {
+			numFlag = true
+		} else if s[i] == '.' && !dotFlag && !eFlag {
+			dotFlag = true
+		} else if (s[i] == 'e' || s[i] == 'E') && !eFlag && numFlag {
+			eFlag = true
+			numFlag = false // reJudge integer after 'e' or 'E'
+		} else if (s[i] == '+' || s[i] == '-') && (i == 0 || s[i-1] == 'e' || s[i-1] == 'E') {
+			continue
+		} else {
+			return false
+		}
+	}
+	// avoid case: s == '.' or 'e/E' or '+/-' and etc...
+	// string s must have num
+	return numFlag
+}
+
+```