mirror of
https://github.com/halfrost/LeetCode-Go.git
synced 2025-07-09 20:32:07 +08:00
@ -21,50 +21,42 @@ func levelOrder(root *TreeNode) [][]int {
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if root == nil {
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if root == nil {
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return [][]int{}
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return [][]int{}
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}
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}
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queue := []*TreeNode{}
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queue := []*TreeNode{root}
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queue = append(queue, root)
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res := make([][]int, 0)
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curNum, nextLevelNum, res, tmp := 1, 0, [][]int{}, []int{}
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for len(queue) > 0 {
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for len(queue) != 0 {
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l := len(queue)
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if curNum > 0 {
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tmp := make([]int, 0, l)
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node := queue[0]
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for i := 0; i < l; i++ {
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if node.Left != nil {
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if queue[i].Left != nil {
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queue = append(queue, node.Left)
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queue = append(queue, queue[i].Left)
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nextLevelNum++
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}
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}
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if node.Right != nil {
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if queue[i].Right != nil {
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queue = append(queue, node.Right)
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queue = append(queue, queue[i].Right)
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nextLevelNum++
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}
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}
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curNum--
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tmp = append(tmp, queue[i].Val)
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tmp = append(tmp, node.Val)
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queue = queue[1:]
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}
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if curNum == 0 {
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res = append(res, tmp)
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curNum = nextLevelNum
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nextLevelNum = 0
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tmp = []int{}
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}
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}
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queue = queue[l:]
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res = append(res, tmp)
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}
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}
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return res
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return res
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}
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}
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// 解法二 DFS
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// 解法二 DFS
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func levelOrder1(root *TreeNode) [][]int {
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func levelOrder1(root *TreeNode) [][]int {
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levels := [][]int{}
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var res [][]int
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dfsLevel(root, -1, &levels)
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var dfsLevel func(node *TreeNode, level int)
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return levels
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dfsLevel = func(node *TreeNode, level int) {
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}
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if node == nil {
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return
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func dfsLevel(node *TreeNode, level int, res *[][]int) {
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}
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if node == nil {
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if len(res) == level {
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return
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res = append(res, []int{node.Val})
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} else {
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res[level] = append(res[level], node.Val)
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}
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dfsLevel(node.Left, level+1)
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dfsLevel(node.Right, level+1)
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}
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}
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currLevel := level + 1
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dfsLevel(root, 0)
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for len(*res) <= currLevel {
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return res
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*res = append(*res, []int{})
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}
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(*res)[currLevel] = append((*res)[currLevel], node.Val)
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dfsLevel(node.Left, currLevel, res)
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dfsLevel(node.Right, currLevel, res)
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}
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}
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@ -50,6 +50,13 @@ return its level order traversal as:
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package leetcode
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package leetcode
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import (
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"github.com/halfrost/LeetCode-Go/structures"
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)
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// TreeNode define
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type TreeNode = structures.TreeNode
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/**
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/**
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* Definition for a binary tree node.
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* Definition for a binary tree node.
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* type TreeNode struct {
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* type TreeNode struct {
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@ -64,53 +71,46 @@ func levelOrder(root *TreeNode) [][]int {
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if root == nil {
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if root == nil {
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return [][]int{}
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return [][]int{}
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}
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}
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queue := []*TreeNode{}
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queue := []*TreeNode{root}
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queue = append(queue, root)
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res := make([][]int, 0)
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curNum, nextLevelNum, res, tmp := 1, 0, [][]int{}, []int{}
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for len(queue) > 0 {
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for len(queue) != 0 {
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l := len(queue)
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if curNum > 0 {
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tmp := make([]int, 0, l)
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node := queue[0]
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for i := 0; i < l; i++ {
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if node.Left != nil {
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if queue[i].Left != nil {
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queue = append(queue, node.Left)
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queue = append(queue, queue[i].Left)
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nextLevelNum++
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}
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}
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if node.Right != nil {
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if queue[i].Right != nil {
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queue = append(queue, node.Right)
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queue = append(queue, queue[i].Right)
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nextLevelNum++
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}
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}
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curNum--
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tmp = append(tmp, queue[i].Val)
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tmp = append(tmp, node.Val)
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queue = queue[1:]
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}
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if curNum == 0 {
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res = append(res, tmp)
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curNum = nextLevelNum
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nextLevelNum = 0
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tmp = []int{}
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}
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}
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queue = queue[l:]
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res = append(res, tmp)
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}
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}
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return res
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return res
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}
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}
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// 解法二 DFS
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// 解法二 DFS
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func levelOrder1(root *TreeNode) [][]int {
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func levelOrder1(root *TreeNode) [][]int {
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levels := [][]int{}
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var res [][]int
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dfsLevel(root, -1, &levels)
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var dfsLevel func(node *TreeNode, level int)
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return levels
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dfsLevel = func(node *TreeNode, level int) {
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if node == nil {
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return
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}
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if len(res) == level {
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res = append(res, []int{node.Val})
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} else {
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res[level] = append(res[level], node.Val)
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}
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dfsLevel(node.Left, level+1)
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dfsLevel(node.Right, level+1)
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}
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dfsLevel(root, 0)
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return res
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}
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}
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func dfsLevel(node *TreeNode, level int, res *[][]int) {
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if node == nil {
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return
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}
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currLevel := level + 1
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for len(*res) <= currLevel {
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*res = append(*res, []int{})
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}
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(*res)[currLevel] = append((*res)[currLevel], node.Val)
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dfsLevel(node.Left, currLevel, res)
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dfsLevel(node.Right, currLevel, res)
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}
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```
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```
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Reference in New Issue
Block a user