Merge pull request #85 from frankegoesdown/1436-Cherry-Pickup-II

1436 cherry pickup ii
This commit is contained in:
halfrost
2021-01-25 16:49:47 +08:00
committed by GitHub
3 changed files with 160 additions and 0 deletions

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package leetcode
func cherryPickup(grid [][]int) int {
m, n := len(grid), len(grid[0])
old, new := make([]int, n*n), make([]int, n*n)
for i := range old {
old[i] = -0xffffff
}
old[n-1] = grid[0][0]+grid[0][n-1]
// dp
for k:=1; k<m; k++ {
for s:=0; s<n*n; s++ {
new[s] = -0xffffff
c1, c2 := s/n, s%n
toadd := grid[k][c1]
if c1 != c2 {
toadd += grid[k][c2]
}
for _, d1 := range []int{1,0,-1} {
for _, d2 := range []int{1,0,-1} {
nc1, nc2 := c1+d1, c2+d2
if nc1>=0 && nc1<n && nc2>=0 && nc2<n && old[nc1*n+nc2]>=0 {
new[s] = max(new[s], old[nc1*n+nc2]+toadd)
}
}
}
}
old, new = new, old
}
allmax := 0
for _, v := range old {
if v>allmax {
allmax = v
}
}
return allmax
}
func max(a, b int) int {
if a>b {
return a
}
return b
}

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package leetcode
import (
"fmt"
"testing"
)
type question1436 struct {
para1436
ans1436
}
type para1436 struct {
grid [][]int
}
type ans1436 struct {
ans int
}
func Test_Problem1436(t *testing.T) {
qs := []question1436{
{
para1436{[][]int{
{3, 1, 1},
{2, 5, 1},
{1, 5, 5},
{2, 1, 1},
}},
ans1436{24},
},
{
para1436{[][]int{
{1, 0, 0, 0, 0, 0, 1},
{2, 0, 0, 0, 0, 3, 0},
{2, 0, 9, 0, 0, 0, 0},
{0, 3, 0, 5, 4, 0, 0},
{1, 0, 2, 3, 0, 0, 6},
}},
ans1436{28},
},
{
para1436{[][]int{
{1, 0, 0, 3},
{0, 0, 0, 3},
{0, 0, 3, 3},
{9, 0, 3, 3},
}},
ans1436{22},
},
{
para1436{[][]int{
{1, 1},
{1, 1},
}},
ans1436{4},
},
}
fmt.Printf("------------------------Leetcode Problem 1436------------------------\n")
for _, q := range qs {
_, p := q.ans1436, q.para1436
fmt.Printf("【input】:%v ", p)
fmt.Printf("【output】:%v \n", cherryPickup(p.grid))
}
fmt.Printf("\n\n\n")
}

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# [1463. Cherry Pickup II](https://leetcode.com/problems/cherry-pickup-ii/)
Given a rows x cols matrix grid representing a field of cherries. Each cell in grid represents the number of cherries that you can collect.
You have two robots that can collect cherries for you, Robot #1 is located at the top-left corner (0,0) , and Robot #2 is located at the top-right corner (0, cols-1) of the grid.
Return the maximum number of cherries collection using both robots by following the rules below:
From a cell (i,j), robots can move to cell (i+1, j-1) , (i+1, j) or (i+1, j+1).
When any robot is passing through a cell, It picks it up all cherries, and the cell becomes an empty cell (0).
When both robots stay on the same cell, only one of them takes the cherries.
Both robots cannot move outside of the grid at any moment.
Both robots should reach the bottom row in the grid.
## Example 1:
```
Input: grid = [[3,1,1],[2,5,1],[1,5,5],[2,1,1]]
Output: 24
Explanation: Path of robot #1 and #2 are described in color green and blue respectively.
Cherries taken by Robot #1, (3 + 2 + 5 + 2) = 12.
Cherries taken by Robot #2, (1 + 5 + 5 + 1) = 12.
Total of cherries: 12 + 12 = 24.
```
## Example 2:
```
Input: grid = [[1,0,0,0,0,0,1],[2,0,0,0,0,3,0],[2,0,9,0,0,0,0],[0,3,0,5,4,0,0],[1,0,2,3,0,0,6]]
Output: 28
Explanation: Path of robot #1 and #2 are described in color green and blue respectively.
Cherries taken by Robot #1, (1 + 9 + 5 + 2) = 17.
Cherries taken by Robot #2, (1 + 3 + 4 + 3) = 11.
Total of cherries: 17 + 11 = 28.
```
## Example 3:
```
Input: grid = [[1,0,0,3],[0,0,0,3],[0,0,3,3],[9,0,3,3]]
Output: 22
```
## Example 4:
```
Input: grid = [[1,1],[1,1]]
Output: 4
```