From a2859d035903617bde960c7c96d9b16720db838a Mon Sep 17 00:00:00 2001 From: tphyhFighting <2363176358@qq.com> Date: Wed, 10 Nov 2021 14:46:35 +0800 Subject: [PATCH] add: leetcode 0495 readme --- leetcode/0495.Teemo-Attacking/README.md | 83 +++++++++++++++++++++++++ 1 file changed, 83 insertions(+) create mode 100644 leetcode/0495.Teemo-Attacking/README.md diff --git a/leetcode/0495.Teemo-Attacking/README.md b/leetcode/0495.Teemo-Attacking/README.md new file mode 100644 index 00000000..fb70c33e --- /dev/null +++ b/leetcode/0495.Teemo-Attacking/README.md @@ -0,0 +1,83 @@ +# [495. Teemo Attacking](https://leetcode-cn.com/problems/teemo-attacking/) + + +## 题目 + +Our hero Teemo is attacking an enemy Ashe with poison attacks! When Teemo attacks Ashe, Ashe gets poisoned for a exactly duration seconds. + +More formally, an attack at second t will mean Ashe is poisoned during the inclusive time interval [t, t + duration - 1]. + +If Teemo attacks again before the poison effect ends, the timer for it is reset, and the poison effect will end duration seconds after the new attack. + +You are given a non-decreasing integer array timeSeries, where timeSeries[i] denotes that Teemo attacks Ashe at second timeSeries[i], and an integer duration. + +Return the total number of seconds that Ashe is poisoned. + +**Example 1**: +``` +Input: timeSeries = [1,4], duration = 2 +Output: 4 +Explanation: Teemo's attacks on Ashe go as follows: +- At second 1, Teemo attacks, and Ashe is poisoned for seconds 1 and 2. +- At second 4, Teemo attacks, and Ashe is poisoned for seconds 4 and 5. +Ashe is poisoned for seconds 1, 2, 4, and 5, which is 4 seconds in total. +``` + +**Example 2**: +``` +Input: timeSeries = [1,2], duration = 2 +Output: 3 +Explanation: Teemo's attacks on Ashe go as follows: +- At second 1, Teemo attacks, and Ashe is poisoned for seconds 1 and 2. +- At second 2 however, Teemo attacks again and resets the poison timer. Ashe is poisoned for seconds 2 and 3. +Ashe is poisoned for seconds 1, 2, and 3, which is 3 seconds in total. +``` + +**Constraints**: + +- 1 <= timeSeries.length <= 10000 +- 0 <= timeSeries[i], duration <= 10000000 +- timeSeries is sorted in non-decreasing order. + +## 题目大意 + +在《英雄联盟》的世界中,有一个叫 “提莫” 的英雄。他的攻击可以让敌方英雄艾希(编者注:寒冰射手)进入中毒状态。 + +当提莫攻击艾希,艾希的中毒状态正好持续duration 秒。 + +正式地讲,提莫在t发起发起攻击意味着艾希在时间区间 [t, t + duration - 1](含 t 和 t + duration - 1)处于中毒状态。 + +如果提莫在中毒影响结束前再次攻击,中毒状态计时器将会重置,在新的攻击之后,中毒影响将会在duration秒后结束。 + +给你一个非递减的整数数组timeSeries,其中timeSeries[i]表示提莫在timeSeries[i]秒时对艾希发起攻击,以及一个表示中毒持续时间的整数duration 。 + +返回艾希处于中毒状态的总秒数。 + +## 解题思路 + +- i从1开始计数,令t等于timeSeries[i - 1] +- 比较end(t + duration - 1)和timeSeries[i]的大小, + - 如果end小于timeSeries[i],ans+=duration + - 否则ans += timeSeries[i] - t +- ans += duration并返回ans + +## 代码 + +```go +package leetcode + +func findPoisonedDuration(timeSeries []int, duration int) int { + var ans int + for i := 1; i < len(timeSeries); i++ { + t := timeSeries[i-1] + end := t + duration - 1 + if end < timeSeries[i] { + ans += duration + } else { + ans += timeSeries[i] - t + } + } + ans += duration + return ans +} +```