Add solution 0643

This commit is contained in:
YDZ
2021-02-07 17:32:15 +08:00
parent 10307418dc
commit 8d2a3414c1
11 changed files with 228 additions and 40 deletions

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package leetcode
func findMaxAverage(nums []int, k int) float64 {
sum := 0
for _, v := range nums[:k] {
sum += v
}
maxSum := sum
for i := k; i < len(nums); i++ {
sum = sum - nums[i-k] + nums[i]
maxSum = max(maxSum, sum)
}
return float64(maxSum) / float64(k)
}
func max(a, b int) int {
if a > b {
return a
}
return b
}

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package leetcode
import (
"fmt"
"testing"
)
type question643 struct {
para643
ans643
}
// para 是参数
// one 代表第一个参数
type para643 struct {
nums []int
k int
}
// ans 是答案
// one 代表第一个答案
type ans643 struct {
one float64
}
func Test_Problem643(t *testing.T) {
qs := []question643{
{
para643{[]int{1, 12, -5, -6, 50, 3}, 4},
ans643{12.75},
},
}
fmt.Printf("------------------------Leetcode Problem 643------------------------\n")
for _, q := range qs {
_, p := q.ans643, q.para643
fmt.Printf("【input】:%v 【output】:%v\n", p, findMaxAverage(p.nums, p.k))
}
fmt.Printf("\n\n\n")
}

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# 643. Maximum Average Subarray I
Added By: halfrost
Created Time: Feb 7, 2021 5:07 PM
Difficulty: Easy
Link: https://leetcode.com/problems/maximum-average-subarray-i/
Tags: Array
## 题目
Given an array consisting of `n` integers, find the contiguous subarray of given length `k` that has the maximum average value. And you need to output the maximum average value.
**Example 1:**
```
Input: [1,12,-5,-6,50,3], k = 4
Output: 12.75
Explanation: Maximum average is (12-5-6+50)/4 = 51/4 = 12.75
```
**Note:**
1. 1 <= `k` <= `n` <= 30,000.
2. Elements of the given array will be in the range [-10,000, 10,000].
## 题目大意
给定 n 个整数,找出平均数最大且长度为 k 的连续子数组,并输出该最大平均数。
## 解题思路
- 简单题。循环一次,扫描数组过程中累加窗口大小为 k 的元素值。不断更新这个最大值。循环结束求出平均值即可。
## 代码
```go
package leetcode
func findMaxAverage(nums []int, k int) float64 {
sum := 0
for _, v := range nums[:k] {
sum += v
}
maxSum := sum
for i := k; i < len(nums); i++ {
sum = sum - nums[i-k] + nums[i]
maxSum = max(maxSum, sum)
}
return float64(maxSum) / float64(k)
}
func max(a, b int) int {
if a > b {
return a
}
return b
}
```