Update 383 solution

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halfrost
2021-12-13 21:21:21 +08:00
parent 481b1ddfa1
commit 7d760f1091
7 changed files with 79 additions and 6 deletions

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@ -138,5 +138,5 @@ func (p *pq) Pop() interface{} {
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# [383. Ransom Note](https://leetcode.com/problems/ransom-note/)
## 题目
Given two stings ransomNote and magazine, return true if ransomNote can be constructed from magazine and false otherwise.
Each letter in magazine can only be used once in ransomNote.
**Example 1**:
Input: ransomNote = "a", magazine = "b"
Output: false
**Example 2**:
Input: ransomNote = "aa", magazine = "ab"
Output: false
**Example 3**:
Input: ransomNote = "aa", magazine = "aab"
Output: true
**Constraints:**
- 1 <= ransomNote.length, magazine.length <= 100000
- ransomNote and magazine consist of lowercase English letters.
## 题目大意
为了不在赎金信中暴露字迹,从杂志上搜索各个需要的字母,组成单词来表达意思。
给你一个赎金信 (ransomNote) 字符串和一个杂志(magazine)字符串,判断 ransomNote 能不能由 magazines 里面的字符构成。
如果可以构成,返回 true ;否则返回 false 。
magazine 中的每个字符只能在 ransomNote 中使用一次。
## 解题思路
- ransomNote 和 magazine 都是由小写字母组成,所以用数组进行简单的字符统计
## 代码
````go
package leetcode
func canConstruct(ransomNote string, magazine string) bool {
if len(ransomNote) > len(magazine) {
return false
}
var cnt [26]int
for _, v := range magazine {
cnt[v-'a']++
}
for _, v := range ransomNote {
cnt[v-'a']--
if cnt[v-'a'] < 0 {
return false
}
}
return true
}
````
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@ -84,6 +84,6 @@ func (this *Solution) Shuffle() []int {
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