Add solution 1486

leetcode/1486.XOR-Operation-in-an-Array/1486. XOR Operation in an Array.go

@@ -0,0 +1,9 @@
+package leetcode
+
+func xorOperation(n int, start int) int {
+	res := 0
+	for i := 0; i < n; i++ {
+		res ^= start + 2*i
+	}
+	return res
+}

leetcode/1486.XOR-Operation-in-an-Array/1486. XOR Operation in an Array_test.go

@@ -0,0 +1,58 @@
+package leetcode
+
+import (
+	"fmt"
+	"testing"
+)
+
+type question1486 struct {
+	para1486
+	ans1486
+}
+
+// para 是参数
+// one 代表第一个参数
+type para1486 struct {
+	n     int
+	start int
+}
+
+// ans 是答案
+// one 代表第一个答案
+type ans1486 struct {
+	one int
+}
+
+func Test_Problem1486(t *testing.T) {
+
+	qs := []question1486{
+
+		{
+			para1486{5, 0},
+			ans1486{8},
+		},
+
+		{
+			para1486{4, 3},
+			ans1486{8},
+		},
+
+		{
+			para1486{1, 7},
+			ans1486{7},
+		},
+
+		{
+			para1486{10, 5},
+			ans1486{2},
+		},
+	}
+
+	fmt.Printf("------------------------Leetcode Problem 1486------------------------\n")
+
+	for _, q := range qs {
+		_, p := q.ans1486, q.para1486
+		fmt.Printf("【input】:%v      【output】:%v      \n", p, xorOperation(p.n, p.start))
+	}
+	fmt.Printf("\n\n\n")
+}

leetcode/1486.XOR-Operation-in-an-Array/README.md

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+# [1486. XOR Operation in an Array](https://leetcode.com/problems/xor-operation-in-an-array/)
+
+
+## 题目
+
+Given an integer `n` and an integer `start`.
+
+Define an array `nums` where `nums[i] = start + 2*i` (0-indexed) and `n == nums.length`.
+
+Return the bitwise XOR of all elements of `nums`.
+
+**Example 1:**
+
+```
+Input: n = 5, start = 0
+Output: 8
+Explanation:Array nums is equal to [0, 2, 4, 6, 8] where (0 ^ 2 ^ 4 ^ 6 ^ 8) = 8.
+Where "^" corresponds to bitwise XOR operator.
+```
+
+**Example 2:**
+
+```
+Input: n = 4, start = 3
+Output: 8
+Explanation:Array nums is equal to [3, 5, 7, 9] where (3 ^ 5 ^ 7 ^ 9) = 8.
+```
+
+**Example 3:**
+
+```
+Input: n = 1, start = 7
+Output: 7
+```
+
+**Example 4:**
+
+```
+Input: n = 10, start = 5
+Output: 2
+```
+
+**Constraints:**
+
+- `1 <= n <= 1000`
+- `0 <= start <= 1000`
+- `n == nums.length`
+
+## 题目大意
+
+给你两个整数，n 和 start 。数组 nums 定义为：nums[i] = start + 2*i（下标从 0 开始）且 n == nums.length 。请返回 nums 中所有元素按位异或（XOR）后得到的结果。
+
+## 解题思路
+
+- 简单题。按照题意，一层循环依次累积异或数组中每个元素。
+
+## 代码
+
+```go
+package leetcode
+
+func xorOperation(n int, start int) int {
+	res := 0
+	for i := 0; i < n; i++ {
+		res ^= start + 2*i
+	}
+	return res
+}
+```