规范格式

leetcode/0856.Score-of-Parentheses/856. Score of Parentheses.go

@@ -0,0 +1,33 @@
+package leetcode
+
+func scoreOfParentheses(S string) int {
+	res, stack, top, temp := 0, []int{}, -1, 0
+	for _, s := range S {
+		if s == '(' {
+			stack = append(stack, -1)
+			top++
+		} else {
+			temp = 0
+			for stack[top] != -1 {
+				temp += stack[top]
+				stack = stack[:len(stack)-1]
+				top--
+			}
+			stack = stack[:len(stack)-1]
+			top--
+			if temp == 0 {
+				stack = append(stack, 1)
+				top++
+			} else {
+				stack = append(stack, temp*2)
+				top++
+			}
+		}
+	}
+	for len(stack) != 0 {
+		res += stack[top]
+		stack = stack[:len(stack)-1]
+		top--
+	}
+	return res
+}

leetcode/0856.Score-of-Parentheses/856. Score of Parentheses_test.go

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+package leetcode
+
+import (
+	"fmt"
+	"testing"
+)
+
+type question856 struct {
+	para856
+	ans856
+}
+
+// para 是参数
+// one 代表第一个参数
+type para856 struct {
+	one string
+}
+
+// ans 是答案
+// one 代表第一个答案
+type ans856 struct {
+	one int
+}
+
+func Test_Problem856(t *testing.T) {
+
+	qs := []question856{
+		question856{
+			para856{"()"},
+			ans856{1},
+		},
+
+		question856{
+			para856{"(())"},
+			ans856{2},
+		},
+
+		question856{
+			para856{"()()"},
+			ans856{2},
+		},
+
+		question856{
+			para856{"(()(()))"},
+			ans856{6},
+		},
+
+		question856{
+			para856{"()(())"},
+			ans856{3},
+		},
+
+		question856{
+			para856{"((()()))"},
+			ans856{8},
+		},
+	}
+
+	fmt.Printf("------------------------Leetcode Problem 856------------------------\n")
+
+	for _, q := range qs {
+		_, p := q.ans856, q.para856
+		fmt.Printf("【input】:%v       【output】:%v\n", p, scoreOfParentheses(p.one))
+	}
+	fmt.Printf("\n\n\n")
+}

leetcode/0856.Score-of-Parentheses/README.md

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+# [856. Score of Parentheses](https://leetcode.com/problems/score-of-parentheses/)
+
+## 题目
+
+Given a balanced parentheses string S, compute the score of the string based on the following rule:
+
+() has score 1
+AB has score A + B, where A and B are balanced parentheses strings.
+(A) has score 2 * A, where A is a balanced parentheses string.
+ 
+
+Example 1:
+
+```c
+Input: "()"
+Output: 1
+
+```
+
+Example 2:
+
+```c
+Input: "(())"
+Output: 2
+```
+
+Example 3:
+
+```c
+Input: "()()"
+Output: 2
+```
+
+Example 4:
+
+```c
+Input: "(()(()))"
+Output: 6
+```
+ 
+
+Note:
+
+1. S is a balanced parentheses string, containing only ( and ).
+2. 2 <= S.length <= 50
+
+## 题目大意
+
+按照以下规则计算括号的分数：() 代表 1 分。AB 代表 A + B，A 和 B 分别是已经满足匹配规则的括号组。(A) 代表 2 * A，其中 A 也是已经满足匹配规则的括号组。给出一个括号字符串，要求按照这些规则计算出括号的分数值。
+
+
+## 解题思路
+
+按照括号匹配的原则，一步步的计算每个组合的分数入栈。遇到题目中的 3 种情况，取出栈顶元素算分数。