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33
leetcode/0705.Design-HashSet/705. Design HashSet.go
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33
leetcode/0705.Design-HashSet/705. Design HashSet.go
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package leetcode
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type MyHashSet struct {
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data []bool
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}
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/** Initialize your data structure here. */
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func Constructor705() MyHashSet {
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return MyHashSet{
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data: make([]bool, 1000001),
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}
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}
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func (this *MyHashSet) Add(key int) {
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this.data[key] = true
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}
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func (this *MyHashSet) Remove(key int) {
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this.data[key] = false
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}
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/** Returns true if this set contains the specified element */
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func (this *MyHashSet) Contains(key int) bool {
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return this.data[key]
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}
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/**
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* Your MyHashSet object will be instantiated and called as such:
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* obj := Constructor();
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* obj.Add(key);
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* obj.Remove(key);
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* param_3 := obj.Contains(key);
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*/
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24
leetcode/0705.Design-HashSet/705. Design HashSet_test.go
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24
leetcode/0705.Design-HashSet/705. Design HashSet_test.go
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package leetcode
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import (
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"fmt"
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"testing"
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)
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func Test_Problem705(t *testing.T) {
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obj := Constructor705()
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obj.Add(7)
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fmt.Printf("Contains 7 = %v\n", obj.Contains(7))
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obj.Remove(10)
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fmt.Printf("Contains 10 = %v\n", obj.Contains(10))
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obj.Add(20)
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fmt.Printf("Contains 20 = %v\n", obj.Contains(20))
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obj.Remove(30)
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fmt.Printf("Contains 30 = %v\n", obj.Contains(30))
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obj.Add(8)
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fmt.Printf("Contains 8 = %v\n", obj.Contains(8))
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obj.Remove(8)
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fmt.Printf("Contains 8 = %v\n", obj.Contains(8))
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param1 := obj.Contains(7)
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fmt.Printf("param1 = %v\n", param1)
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}
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53
leetcode/0705.Design-HashSet/README.md
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53
leetcode/0705.Design-HashSet/README.md
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# [705. Design HashSet](https://leetcode.com/problems/design-hashset/)
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## 题目:
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Design a HashSet without using any built-in hash table libraries.
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To be specific, your design should include these functions:
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- `add(value)`: Insert a value into the HashSet.
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- `contains(value)` : Return whether the value exists in the HashSet or not.
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- `remove(value)`: Remove a value in the HashSet. If the value does not exist in the HashSet, do nothing.
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**Example:**
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MyHashSet hashSet = new MyHashSet();
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hashSet.add(1);
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hashSet.add(2);
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hashSet.contains(1); // returns true
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hashSet.contains(3); // returns false (not found)
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hashSet.add(2);
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hashSet.contains(2); // returns true
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hashSet.remove(2);
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hashSet.contains(2); // returns false (already removed)
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**Note:**
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- All values will be in the range of `[0, 1000000]`.
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- The number of operations will be in the range of `[1, 10000]`.
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- Please do not use the built-in HashSet library.
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## 题目大意
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不使用任何内建的哈希表库设计一个哈希集合具体地说,你的设计应该包含以下的功能:
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- add(value):向哈希集合中插入一个值。
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- contains(value) :返回哈希集合中是否存在这个值。
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- remove(value):将给定值从哈希集合中删除。如果哈希集合中没有这个值,什么也不做。
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注意:
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- 所有的值都在 [1, 1000000] 的范围内。
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- 操作的总数目在 [1, 10000] 范围内。
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- 不要使用内建的哈希集合库。
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## 解题思路
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- 简单题,设计一个 hashset 的数据结构,要求有 `add(value)`,`contains(value)`,`remove(value)`,这 3 个方法。
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