规范格式

leetcode/0693.Binary-Number-with-Alternating-Bits/693. Binary Number with Alternating Bits.go

@@ -0,0 +1,29 @@
+package leetcode
+
+// 解法一
+func hasAlternatingBits(n int) bool {
+	/*
+	   n =         1 0 1 0 1 0 1 0
+	   n >> 1      0 1 0 1 0 1 0 1
+	   n ^ n>>1    1 1 1 1 1 1 1 1
+	   n           1 1 1 1 1 1 1 1
+	   n + 1     1 0 0 0 0 0 0 0 0
+	   n & (n+1)   0 0 0 0 0 0 0 0
+	*/
+	n = n ^ (n >> 1)
+	return (n & (n + 1)) == 0
+}
+
+// 解法二
+func hasAlternatingBits1(n int) bool {
+	last, current := 0, 0
+	for n > 0 {
+		last = n & 1
+		n = n / 2
+		current = n & 1
+		if last == current {
+			return false
+		}
+	}
+	return true
+}