规范格式

This commit is contained in:
YDZ
2020-08-07 15:50:06 +08:00
parent 854a339abc
commit 4e11f4028a
1438 changed files with 907 additions and 924 deletions

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package leetcode
import (
"github.com/halfrost/LeetCode-Go/structures"
)
// TreeNode define
type TreeNode = structures.TreeNode
/**
* Definition for a binary tree node.
* type TreeNode struct {
* Val int
* Left *TreeNode
* Right *TreeNode
* }
*/
func buildTree(preorder []int, inorder []int) *TreeNode {
inPos := make(map[int]int)
for i := 0; i < len(inorder); i++ {
inPos[inorder[i]] = i
}
return buildPreIn2TreeDFS(preorder, 0, len(preorder)-1, 0, inPos)
}
func buildPreIn2TreeDFS(pre []int, preStart int, preEnd int, inStart int, inPos map[int]int) *TreeNode {
if preStart > preEnd {
return nil
}
root := &TreeNode{Val: pre[preStart]}
rootIdx := inPos[pre[preStart]]
leftLen := rootIdx - inStart
root.Left = buildPreIn2TreeDFS(pre, preStart+1, preStart+leftLen, inStart, inPos)
root.Right = buildPreIn2TreeDFS(pre, preStart+leftLen+1, preEnd, rootIdx+1, inPos)
return root
}

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package leetcode
import (
"fmt"
"testing"
"github.com/halfrost/LeetCode-Go/structures"
)
type question105 struct {
para105
ans105
}
// para 是参数
// one 代表第一个参数
type para105 struct {
preorder []int
inorder []int
}
// ans 是答案
// one 代表第一个答案
type ans105 struct {
one []int
}
func Test_Problem105(t *testing.T) {
qs := []question105{
question105{
para105{[]int{3, 9, 20, 15, 7}, []int{9, 3, 15, 20, 7}},
ans105{[]int{3, 9, 20, structures.NULL, structures.NULL, 15, 7}},
},
}
fmt.Printf("------------------------Leetcode Problem 105------------------------\n")
for _, q := range qs {
_, p := q.ans105, q.para105
fmt.Printf("【input】:%v ", p)
fmt.Printf("【output】:%v \n", structures.Tree2ints(buildTree(p.preorder, p.inorder)))
}
fmt.Printf("\n\n\n")
}

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# [105. Construct Binary Tree from Preorder and Inorder Traversal](https://leetcode.com/problems/construct-binary-tree-from-preorder-and-inorder-traversal/)
## 题目:
Given preorder and inorder traversal of a tree, construct the binary tree.
**Note:**You may assume that duplicates do not exist in the tree.
For example, given
preorder = [3,9,20,15,7]
inorder = [9,3,15,20,7]
Return the following binary tree:
3
/ \
9 20
/ \
15 7
## 题目大意
根据一棵树的前序遍历与中序遍历构造二叉树。
注意:
你可以假设树中没有重复的元素。
## 解题思路
- 给出 2 个数组,根据 preorder 和 inorder 数组构造一颗树。
- 利用递归思想,从 preorder 可以得到根节点,从 inorder 中得到左子树和右子树。只剩一个节点的时候即为根节点。不断的递归直到所有的树都生成完成。