mirror of
https://github.com/halfrost/LeetCode-Go.git
synced 2025-07-05 00:25:22 +08:00
规范格式
This commit is contained in:
@ -0,0 +1,37 @@
|
||||
package leetcode
|
||||
|
||||
import (
|
||||
"github.com/halfrost/LeetCode-Go/structures"
|
||||
)
|
||||
|
||||
// TreeNode define
|
||||
type TreeNode = structures.TreeNode
|
||||
|
||||
/**
|
||||
* Definition for a binary tree node.
|
||||
* type TreeNode struct {
|
||||
* Val int
|
||||
* Left *TreeNode
|
||||
* Right *TreeNode
|
||||
* }
|
||||
*/
|
||||
|
||||
func buildTree(preorder []int, inorder []int) *TreeNode {
|
||||
inPos := make(map[int]int)
|
||||
for i := 0; i < len(inorder); i++ {
|
||||
inPos[inorder[i]] = i
|
||||
}
|
||||
return buildPreIn2TreeDFS(preorder, 0, len(preorder)-1, 0, inPos)
|
||||
}
|
||||
|
||||
func buildPreIn2TreeDFS(pre []int, preStart int, preEnd int, inStart int, inPos map[int]int) *TreeNode {
|
||||
if preStart > preEnd {
|
||||
return nil
|
||||
}
|
||||
root := &TreeNode{Val: pre[preStart]}
|
||||
rootIdx := inPos[pre[preStart]]
|
||||
leftLen := rootIdx - inStart
|
||||
root.Left = buildPreIn2TreeDFS(pre, preStart+1, preStart+leftLen, inStart, inPos)
|
||||
root.Right = buildPreIn2TreeDFS(pre, preStart+leftLen+1, preEnd, rootIdx+1, inPos)
|
||||
return root
|
||||
}
|
@ -0,0 +1,46 @@
|
||||
package leetcode
|
||||
|
||||
import (
|
||||
"fmt"
|
||||
"testing"
|
||||
|
||||
"github.com/halfrost/LeetCode-Go/structures"
|
||||
)
|
||||
|
||||
type question105 struct {
|
||||
para105
|
||||
ans105
|
||||
}
|
||||
|
||||
// para 是参数
|
||||
// one 代表第一个参数
|
||||
type para105 struct {
|
||||
preorder []int
|
||||
inorder []int
|
||||
}
|
||||
|
||||
// ans 是答案
|
||||
// one 代表第一个答案
|
||||
type ans105 struct {
|
||||
one []int
|
||||
}
|
||||
|
||||
func Test_Problem105(t *testing.T) {
|
||||
|
||||
qs := []question105{
|
||||
|
||||
question105{
|
||||
para105{[]int{3, 9, 20, 15, 7}, []int{9, 3, 15, 20, 7}},
|
||||
ans105{[]int{3, 9, 20, structures.NULL, structures.NULL, 15, 7}},
|
||||
},
|
||||
}
|
||||
|
||||
fmt.Printf("------------------------Leetcode Problem 105------------------------\n")
|
||||
|
||||
for _, q := range qs {
|
||||
_, p := q.ans105, q.para105
|
||||
fmt.Printf("【input】:%v ", p)
|
||||
fmt.Printf("【output】:%v \n", structures.Tree2ints(buildTree(p.preorder, p.inorder)))
|
||||
}
|
||||
fmt.Printf("\n\n\n")
|
||||
}
|
@ -0,0 +1,36 @@
|
||||
# [105. Construct Binary Tree from Preorder and Inorder Traversal](https://leetcode.com/problems/construct-binary-tree-from-preorder-and-inorder-traversal/)
|
||||
|
||||
|
||||
## 题目:
|
||||
|
||||
Given preorder and inorder traversal of a tree, construct the binary tree.
|
||||
|
||||
**Note:**You may assume that duplicates do not exist in the tree.
|
||||
|
||||
For example, given
|
||||
|
||||
preorder = [3,9,20,15,7]
|
||||
inorder = [9,3,15,20,7]
|
||||
|
||||
Return the following binary tree:
|
||||
|
||||
3
|
||||
/ \
|
||||
9 20
|
||||
/ \
|
||||
15 7
|
||||
|
||||
|
||||
|
||||
## 题目大意
|
||||
|
||||
根据一棵树的前序遍历与中序遍历构造二叉树。
|
||||
|
||||
注意:
|
||||
你可以假设树中没有重复的元素。
|
||||
|
||||
|
||||
## 解题思路
|
||||
|
||||
- 给出 2 个数组,根据 preorder 和 inorder 数组构造一颗树。
|
||||
- 利用递归思想,从 preorder 可以得到根节点,从 inorder 中得到左子树和右子树。只剩一个节点的时候即为根节点。不断的递归直到所有的树都生成完成。
|
Reference in New Issue
Block a user