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规范格式
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package leetcode
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import "fmt"
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func largestRectangleArea(heights []int) int {
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maxArea, stack, height := 0, []int{}, 0
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for i := 0; i <= len(heights); i++ {
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if i == len(heights) {
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height = 0
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} else {
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height = heights[i]
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}
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if len(stack) == 0 || height >= heights[stack[len(stack)-1]] {
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stack = append(stack, i)
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} else {
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tmp := stack[len(stack)-1]
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fmt.Printf("1. tmp = %v stack = %v\n", tmp, stack)
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stack = stack[:len(stack)-1]
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length := 0
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if len(stack) == 0 {
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length = i
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} else {
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length = i - 1 - stack[len(stack)-1]
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fmt.Printf("2. length = %v stack = %v i = %v\n", length, stack, i)
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}
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maxArea = max(maxArea, heights[tmp]*length)
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fmt.Printf("3. maxArea = %v heights[tmp]*length = %v\n", maxArea, heights[tmp]*length)
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i--
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}
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}
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return maxArea
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}
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func max(a int, b int) int {
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if a > b {
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return a
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}
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return b
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}
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package leetcode
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import (
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"fmt"
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"testing"
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)
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type question84 struct {
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para84
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ans84
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}
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// para 是参数
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// one 代表第一个参数
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type para84 struct {
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one []int
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}
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// ans 是答案
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// one 代表第一个答案
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type ans84 struct {
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one int
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}
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func Test_Problem84(t *testing.T) {
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qs := []question84{
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question84{
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para84{[]int{2, 1, 5, 6, 2, 3}},
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ans84{10},
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},
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question84{
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para84{[]int{1}},
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ans84{1},
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},
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question84{
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para84{[]int{1, 1}},
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ans84{2},
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},
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}
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fmt.Printf("------------------------Leetcode Problem 84------------------------\n")
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for _, q := range qs {
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_, p := q.ans84, q.para84
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fmt.Printf("【input】:%v 【output】:%v\n", p, largestRectangleArea(p.one))
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}
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fmt.Printf("\n\n\n")
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}
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34
leetcode/0084.Largest-Rectangle-in-Histogram/README.md
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34
leetcode/0084.Largest-Rectangle-in-Histogram/README.md
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# [84. Largest Rectangle in Histogram](https://leetcode.com/problems/largest-rectangle-in-histogram/)
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## 题目
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Given n non-negative integers representing the histogram's bar height where the width of each bar is 1, find the area of largest rectangle in the histogram.
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Above is a histogram where width of each bar is 1, given height = [2,1,5,6,2,3].
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The largest rectangle is shown in the shaded area, which has area = 10 unit.
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Example:
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```c
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Input: [2,1,5,6,2,3]
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Output: 10
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```
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## 题目大意
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给出每个直方图的高度,要求在这些直方图之中找到面积最大的矩形,输出矩形的面积。
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## 解题思路
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用单调栈依次保存直方图的高度下标,一旦出现高度比栈顶元素小的情况就取出栈顶元素,单独计算一下这个栈顶元素的矩形的高度。然后停在这里(外层循环中的 i--,再 ++,就相当于停在这里了),继续取出当前最大栈顶的前一个元素,即连续弹出 2 个最大的,以稍小的一个作为矩形的边,宽就是 2 计算面积…………如果停在这里的下标代表的高度一直比栈里面的元素小,就一直弹出,取出最后一个比当前下标大的高度作为矩形的边。宽就是最后一个比当前下标大的高度和当前下标 i 的差值。计算出面积以后不断的更新 maxArea 即可。
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