规范格式

This commit is contained in:
YDZ
2020-08-07 15:50:06 +08:00
parent 854a339abc
commit 4e11f4028a
1438 changed files with 907 additions and 924 deletions

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package leetcode
func uniquePaths(m int, n int) int {
dp := make([][]int, n)
for i := 0; i < n; i++ {
dp[i] = make([]int, m)
}
for i := 0; i < m; i++ {
dp[0][i] = 1
}
for i := 0; i < n; i++ {
dp[i][0] = 1
}
for i := 1; i < n; i++ {
for j := 1; j < m; j++ {
dp[i][j] = dp[i-1][j] + dp[i][j-1]
}
}
return dp[n-1][m-1]
}

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package leetcode
import (
"fmt"
"testing"
)
type question62 struct {
para62
ans62
}
// para 是参数
// one 代表第一个参数
type para62 struct {
m int
n int
}
// ans 是答案
// one 代表第一个答案
type ans62 struct {
one int
}
func Test_Problem62(t *testing.T) {
qs := []question62{
question62{
para62{3, 2},
ans62{3},
},
question62{
para62{7, 3},
ans62{28},
},
question62{
para62{1, 2},
ans62{1},
},
}
fmt.Printf("------------------------Leetcode Problem 62------------------------\n")
for _, q := range qs {
_, p := q.ans62, q.para62
fmt.Printf("【input】:%v 【output】:%v\n", p, uniquePaths(p.m, p.n))
}
fmt.Printf("\n\n\n")
}

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# [62. Unique Paths](https://leetcode.com/problems/unique-paths/)
## 题目
A robot is located at the top-left corner of a *m* x *n* grid (marked 'Start' in the diagram below).
The robot can only move either down or right at any point in time. The robot is trying to reach the bottom-right corner of the grid (marked 'Finish' in the diagram below).
How many possible unique paths are there?
![](https://assets.leetcode.com/uploads/2018/10/22/robot_maze.png)
Above is a 7 x 3 grid. How many possible unique paths are there?
**Note:** *m* and *n* will be at most 100.
**Example 1:**
Input: m = 3, n = 2
Output: 3
Explanation:
From the top-left corner, there are a total of 3 ways to reach the bottom-right corner:
1. Right -> Right -> Down
2. Right -> Down -> Right
3. Down -> Right -> Right
**Example 2:**
Input: m = 7, n = 3
Output: 28
## 题目大意
一个机器人位于一个 m x n 网格的左上角 起始点在下图中标记为“Start” 。机器人每次只能向下或者向右移动一步。机器人试图达到网格的右下角在下图中标记为“Finish”。问总共有多少条不同的路径
## 解题思路
- 这是一道简单的 DP 题。输出地图上从左上角走到右下角的走法数。
- 由于机器人只能向右走和向下走,所以地图的第一行和第一列的走法数都是 1地图中任意一点的走法数是 `dp[i][j] = dp[i-1][j] + dp[i][j-1]`