Add solution 2022

leetcode/2022.Convert-1D-Array-Into-2D-Array/2022. Convert 1D Array Into 2D Array.go

@@ -0,0 +1,12 @@
+package leetcode
+
+func construct2DArray(original []int, m int, n int) [][]int {
+	if m*n != len(original) {
+		return [][]int{}
+	}
+	res := make([][]int, m)
+	for i := 0; i < m; i++ {
+		res[i] = original[n*i : n*(i+1)]
+	}
+	return res
+}

leetcode/2022.Convert-1D-Array-Into-2D-Array/2022. Convert 1D Array Into 2D Array_test.go

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+package leetcode
+
+import (
+	"fmt"
+	"testing"
+)
+
+type question2022 struct {
+	para2022
+	ans2022
+}
+
+// para 是参数
+// one 代表第一个参数
+type para2022 struct {
+	original []int
+	m        int
+	n        int
+}
+
+// ans 是答案
+// one 代表第一个答案
+type ans2022 struct {
+	one [][]int
+}
+
+func Test_Problem2022(t *testing.T) {
+
+	qs := []question2022{
+
+		{
+			para2022{[]int{1, 2, 3, 4}, 2, 2},
+			ans2022{[][]int{{1, 2}, {3, 4}}},
+		},
+
+		{
+			para2022{[]int{1, 2, 3}, 1, 3},
+			ans2022{[][]int{{1, 2, 3}}},
+		},
+
+		{
+			para2022{[]int{1, 2}, 1, 1},
+			ans2022{[][]int{{}}},
+		},
+
+		{
+			para2022{[]int{3}, 1, 2},
+			ans2022{[][]int{{3}}},
+		},
+
+		{
+			para2022{[]int{1, 1, 1, 1}, 4, 1},
+			ans2022{[][]int{{1, 1, 1, 1}}},
+		},
+	}
+
+	fmt.Printf("------------------------Leetcode Problem 2022------------------------\n")
+
+	for _, q := range qs {
+		_, p := q.ans2022, q.para2022
+		fmt.Printf("【input】:%v       【output】:%v\n", p, construct2DArray(p.original, p.m, p.n))
+	}
+	fmt.Printf("\n\n\n")
+}

leetcode/2022.Convert-1D-Array-Into-2D-Array/README.md

@@ -0,0 +1,77 @@
+# [2022. Convert 1D Array Into 2D Array](https://leetcode.com/problems/convert-1d-array-into-2d-array/)
+
+## 题目
+
+You are given a **0-indexed** 1-dimensional (1D) integer array `original`, and two integers, `m` and `n`. You are tasked with creating a 2-dimensional (2D) array with `m` rows and `n` columns using **all** the elements from `original`.
+
+The elements from indices `0` to `n - 1` (**inclusive**) of `original` should form the first row of the constructed 2D array, the elements from indices `n` to `2 * n - 1` (**inclusive**) should form the second row of the constructed 2D array, and so on.
+
+Return *an* `m x n` *2D array constructed according to the above procedure, or an empty 2D array if it is impossible*.
+
+**Example 1:**
+
+![https://assets.leetcode.com/uploads/2021/08/26/image-20210826114243-1.png](https://assets.leetcode.com/uploads/2021/08/26/image-20210826114243-1.png)
+
+```
+Input: original = [1,2,3,4], m = 2, n = 2
+Output: [[1,2],[3,4]]
+Explanation: The constructed 2D array should contain 2 rows and 2 columns.
+The first group of n=2 elements in original, [1,2], becomes the first row in the constructed 2D array.
+The second group of n=2 elements in original, [3,4], becomes the second row in the constructed 2D array.
+
+```
+
+**Example 2:**
+
+```
+Input: original = [1,2,3], m = 1, n = 3
+Output: [[1,2,3]]
+Explanation: The constructed 2D array should contain 1 row and 3 columns.
+Put all three elements in original into the first row of the constructed 2D array.
+
+```
+
+**Example 3:**
+
+```
+Input: original = [1,2], m = 1, n = 1
+Output: []
+Explanation: There are 2 elements in original.
+It is impossible to fit 2 elements in a 1x1 2D array, so return an empty 2D array.
+
+```
+
+**Constraints:**
+
+- `1 <= original.length <= 5 * 104`
+- `1 <= original[i] <= 105`
+- `1 <= m, n <= 4 * 104`
+
+## 题目大意
+
+给你一个下标从 0 开始的一维整数数组 original 和两个整数 m 和  n 。你需要使用 original 中 所有 元素创建一个 m 行 n 列的二维数组。
+
+original 中下标从 0 到 n - 1 （都 包含 ）的元素构成二维数组的第一行，下标从 n 到 2 * n - 1 （都 包含 ）的元素构成二维数组的第二行，依此类推。
+
+请你根据上述过程返回一个 m x n 的二维数组。如果无法构成这样的二维数组，请你返回一个空的二维数组。
+
+## 解题思路
+
+- 简单题。从一维数组 original 中依次取出每行 n 个元素，顺序放到 m 行中。此题中，如果 m*n 大于或者小于 original 的长度，都输出空数组。
+
+## 代码
+
+```go
+package leetcode
+
+func construct2DArray(original []int, m int, n int) [][]int {
+	if m*n != len(original) {
+		return [][]int{}
+	}
+	res := make([][]int, m)
+	for i := 0; i < m; i++ {
+		res[i] = original[n*i : n*(i+1)]
+	}
+	return res
+}
+```