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Add solution 989
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leetcode/0989.Add-to-Array-Form-of-Integer/README.md
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# [989. Add to Array-Form of Integer](https://leetcode.com/problems/add-to-array-form-of-integer/)
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## 题目
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For a non-negative integer `X`, the *array-form of `X`* is an array of its digits in left to right order. For example, if `X = 1231`, then the array form is `[1,2,3,1]`.
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Given the array-form `A` of a non-negative integer `X`, return the array-form of the integer `X+K`.
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**Example 1:**
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```
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Input: A = [1,2,0,0], K = 34
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Output: [1,2,3,4]
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Explanation: 1200 + 34 = 1234
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```
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**Example 2:**
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```
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Input: A = [2,7,4], K = 181
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Output: [4,5,5]
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Explanation: 274 + 181 = 455
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```
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**Example 3:**
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```
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Input: A = [2,1,5], K = 806
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Output: [1,0,2,1]
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Explanation: 215 + 806 = 1021
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```
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**Example 4:**
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```
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Input: A = [9,9,9,9,9,9,9,9,9,9], K = 1
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Output: [1,0,0,0,0,0,0,0,0,0,0]
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Explanation: 9999999999 + 1 = 10000000000
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```
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**Note:**
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1. `1 <= A.length <= 10000`
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2. `0 <= A[i] <= 9`
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3. `0 <= K <= 10000`
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4. If `A.length > 1`, then `A[0] != 0`
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## 题目大意
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对于非负整数 X 而言,X 的数组形式是每位数字按从左到右的顺序形成的数组。例如,如果 X = 1231,那么其数组形式为 [1,2,3,1]。给定非负整数 X 的数组形式 A,返回整数 X+K 的数组形式。
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## 解题思路
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- 简单题,计算 2 个非负整数的和。累加过程中不断的进位,最终输出到数组中记得需要逆序,即数字的高位排在数组下标较小的位置。
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## 代码
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```go
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package leetcode
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func addToArrayForm(A []int, K int) []int {
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res := []int{}
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for i := len(A) - 1; i >= 0; i-- {
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sum := A[i] + K%10
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K /= 10
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if sum >= 10 {
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K++
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sum -= 10
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}
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res = append(res, sum)
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}
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for ; K > 0; K /= 10 {
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res = append(res, K%10)
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}
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reverse(res)
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return res
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}
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func reverse(A []int) {
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for i, n := 0, len(A); i < n/2; i++ {
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A[i], A[n-1-i] = A[n-1-i], A[i]
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}
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}
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```
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