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Add solution 341
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package leetcode
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import "container/list"
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// This is the interface that allows for creating nested lists.
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// You should not implement it, or speculate about its implementation
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type NestedInteger struct {
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}
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// Return true if this NestedInteger holds a single integer, rather than a nested list.
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func (this NestedInteger) IsInteger() bool { return true }
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// Return the single integer that this NestedInteger holds, if it holds a single integer
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// The result is undefined if this NestedInteger holds a nested list
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// So before calling this method, you should have a check
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func (this NestedInteger) GetInteger() int { return 0 }
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// Set this NestedInteger to hold a single integer.
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func (n *NestedInteger) SetInteger(value int) {}
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// Set this NestedInteger to hold a nested list and adds a nested integer to it.
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func (this *NestedInteger) Add(elem NestedInteger) {}
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// Return the nested list that this NestedInteger holds, if it holds a nested list
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// The list length is zero if this NestedInteger holds a single integer
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// You can access NestedInteger's List element directly if you want to modify it
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func (this NestedInteger) GetList() []*NestedInteger { return nil }
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type NestedIterator struct {
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stack *list.List
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}
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type listIndex struct {
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nestedList []*NestedInteger
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index int
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}
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func Constructor(nestedList []*NestedInteger) *NestedIterator {
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stack := list.New()
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stack.PushBack(&listIndex{nestedList, 0})
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return &NestedIterator{stack}
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}
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func (this *NestedIterator) Next() int {
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if !this.HasNext() {
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return -1
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}
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last := this.stack.Back().Value.(*listIndex)
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nestedList, i := last.nestedList, last.index
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val := nestedList[i].GetInteger()
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last.index++
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return val
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}
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func (this *NestedIterator) HasNext() bool {
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stack := this.stack
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for stack.Len() > 0 {
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last := stack.Back().Value.(*listIndex)
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nestedList, i := last.nestedList, last.index
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if i >= len(nestedList) {
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stack.Remove(stack.Back())
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} else {
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val := nestedList[i]
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if val.IsInteger() {
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return true
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}
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last.index++
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stack.PushBack(&listIndex{val.GetList(), 0})
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}
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}
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return false
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}
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