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47 lines
1.1 KiB
JavaScript
47 lines
1.1 KiB
JavaScript
// Problem Statement => https://www.youtube.com/watch?v=lBRtnuxg-gU
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const minCostPath = (matrix) => {
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/*
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Find the min cost path from top-left to bottom-right in matrix
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>>> minCostPath([[2, 1], [3, 1], [4, 2]])
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>>> 6
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*/
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const n = matrix.length
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const m = matrix[0].length
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// moves[i][j] => minimum number of moves to reach cell i, j
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const moves = new Array(n)
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for (let i = 0; i < moves.length; i++) moves[i] = new Array(m)
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// base conditions
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moves[0][0] = matrix[0][0] // to reach cell (0, 0) from (0, 0) is of no moves
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for (let i = 1; i < m; i++) moves[0][i] = moves[0][i - 1] + matrix[0][i]
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for (let i = 1; i < n; i++) moves[i][0] = moves[i - 1][0] + matrix[i][0]
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for (let i = 1; i < n; i++) {
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for (let j = 1; j < m; j++) { moves[i][j] = Math.min(moves[i - 1][j], moves[i][j - 1]) + matrix[i][j] }
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}
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return moves[n - 1][m - 1]
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}
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const main = () => {
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console.log(
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minCostPath([
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[2, 1],
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[3, 1],
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[4, 2]
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])
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)
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console.log(
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minCostPath([
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[2, 1, 4],
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[2, 1, 3],
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[3, 2, 1]
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])
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)
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}
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main()
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