Files
JavaScript/String/CheckRearrangePalindrome.js
Roland Hummel 86d333ee94 feat: Test running overhaul, switch to Prettier & reformat everything (#1407)
* chore: Switch to Node 20 + Vitest

* chore: migrate to vitest mock functions

* chore: code style (switch to prettier)

* test: re-enable long-running test

Seems the switch to Node 20 and Vitest has vastly improved the code's and / or the test's runtime!

see #1193

* chore: code style

* chore: fix failing tests

* Updated Documentation in README.md

* Update contribution guidelines to state usage of Prettier

* fix: set prettier printWidth back to 80

* chore: apply updated code style automatically

* fix: set prettier line endings to lf again

* chore: apply updated code style automatically

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Co-authored-by: github-actions <${GITHUB_ACTOR}@users.noreply.github.com>
Co-authored-by: Lars Müller <34514239+appgurueu@users.noreply.github.com>
2023-10-04 02:38:19 +05:30

38 lines
1.1 KiB
JavaScript

/**
* What is a palindrome? https://en.wikipedia.org/wiki/Palindrome
* Receives a string and returns whether it can be rearranged to become a palindrome or not
* The string can only be a palindrome if the count of ALL characters is even or if the ONLY ONE character count is odd
* Input is a string
*
**/
export const palindromeRearranging = (str) => {
// check that input is a string
if (typeof str !== 'string') {
return 'Not a string'
}
// Check if is a empty string
if (!str) {
return 'Empty string'
}
// First obtain the character count for each character in the string and store it in an object.
// Filter the object's values to only the odd character counts.
const charCounts = [...str].reduce((counts, char) => {
counts[char] = counts[char] ? counts[char] + 1 : 1
return counts
}, {})
// If the length of the resulting array is 0 or 1, the string can be a palindrome.
return (
Object.values(charCounts).filter((count) => count % 2 !== 0).length <= 1
)
}
// testing
// > palindromeRearranging('aaeccrr')
// true
// > palindromeRearranging('leve')
// false