Files
JavaScript/Sorts/SelectionSort.js
Roland Hummel 86d333ee94 feat: Test running overhaul, switch to Prettier & reformat everything (#1407)
* chore: Switch to Node 20 + Vitest

* chore: migrate to vitest mock functions

* chore: code style (switch to prettier)

* test: re-enable long-running test

Seems the switch to Node 20 and Vitest has vastly improved the code's and / or the test's runtime!

see #1193

* chore: code style

* chore: fix failing tests

* Updated Documentation in README.md

* Update contribution guidelines to state usage of Prettier

* fix: set prettier printWidth back to 80

* chore: apply updated code style automatically

* fix: set prettier line endings to lf again

* chore: apply updated code style automatically

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Co-authored-by: github-actions <${GITHUB_ACTOR}@users.noreply.github.com>
Co-authored-by: Lars Müller <34514239+appgurueu@users.noreply.github.com>
2023-10-04 02:38:19 +05:30

38 lines
1.5 KiB
JavaScript

/* The selection sort algorithm sorts an array by repeatedly finding the minimum element
*(considering ascending order) from unsorted part and putting it at the beginning. The
*algorithm maintains two subarrays in a given array.
*1) The subarray which is already sorted.
*2) Remaining subarray which is unsorted.
*
*In every iteration of selection sort, the minimum element (considering ascending order)
*from the unsorted subarray is picked and moved to the sorted subarray.
*/
export const selectionSort = (list) => {
if (!Array.isArray(list)) {
throw new TypeError('Given input is not an array')
}
const items = [...list] // We don't want to modify the original array
const length = items.length
for (let i = 0; i < length - 1; i++) {
if (typeof items[i] !== 'number') {
throw new TypeError('One of the items in your array is not a number')
}
// Number of passes
let min = i // min holds the current minimum number position for each pass; i holds the Initial min number
for (let j = i + 1; j < length; j++) {
// Note that j = i + 1 as we only need to go through unsorted array
if (items[j] < items[min]) {
// Compare the numbers
min = j // Change the current min number position if a smaller num is found
}
}
if (min !== i) {
// After each pass, if the current min num != initial min num, exchange the position.
// Swap the numbers
;[items[i], items[min]] = [items[min], items[i]]
}
}
return items
}