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e9e3ea4684
* Add Tug of War solution using backtracking
* Updated Documentation in README.md
* Added Tug of war problem link
* Updated Documentation in README.md
* Updated Documentation in README.md
* Refactor tugOfWar: remove unused vars, optimize initialization, and remove redundant checks
* Added Function Export Statment
* Updated Documentation in README.md
* Resolved Code Style --Prettier
* Rename "backtrack" to "recurse"
* Fix test case: The difference needs to be exactly 1.
* Code Modification: subsets should have sizes as close to n/2 as possible
* Updated test-case of TugOfWar
* Changed TugOfWar problem to Partition
* Modified partition problem
* Updated Documentation in README.md
* fixed code style
---------
Co-authored-by: github-actions <${GITHUB_ACTOR}@users.noreply.github.com>
Co-authored-by: Lars Müller <34514239+appgurueu@users.noreply.github.com>
25 lines
796 B
JavaScript
25 lines
796 B
JavaScript
import { canPartition } from '../Partition'
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describe('Partition (Recursive)', () => {
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it('expects to return true for an array that can be partitioned', () => {
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const result = canPartition([1, 5, 11, 5])
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expect(result).toBe(true)
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})
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it('expects to return false for an array that cannot be partitioned', () => {
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const result = canPartition([1, 2, 3, 5])
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expect(result).toBe(false)
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})
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it('expects to return true for an empty array (0 elements)', () => {
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const result = canPartition([])
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expect(result).toBe(true)
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})
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it('Throw Error for Invalid Input', () => {
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expect(() => canPartition(123)).toThrow('Invalid Input')
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expect(() => canPartition(null)).toThrow('Invalid Input')
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expect(() => canPartition(undefined)).toThrow('Invalid Input')
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})
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})
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