mirror of
https://github.com/TheAlgorithms/JavaScript.git
synced 2025-07-04 07:29:47 +08:00

* chore: Switch to Node 20 + Vitest * chore: migrate to vitest mock functions * chore: code style (switch to prettier) * test: re-enable long-running test Seems the switch to Node 20 and Vitest has vastly improved the code's and / or the test's runtime! see #1193 * chore: code style * chore: fix failing tests * Updated Documentation in README.md * Update contribution guidelines to state usage of Prettier * fix: set prettier printWidth back to 80 * chore: apply updated code style automatically * fix: set prettier line endings to lf again * chore: apply updated code style automatically --------- Co-authored-by: github-actions <${GITHUB_ACTOR}@users.noreply.github.com> Co-authored-by: Lars Müller <34514239+appgurueu@users.noreply.github.com>
43 lines
1.1 KiB
JavaScript
43 lines
1.1 KiB
JavaScript
/**
|
|
* @function findMaxRecursion
|
|
* @description This algorithm will find the maximum value of a array of numbers.
|
|
*
|
|
* @param {Integer[]} arr Array of numbers
|
|
* @param {Integer} left Index of the first element
|
|
* @param {Integer} right Index of the last element
|
|
*
|
|
* @return {Integer} Maximum value of the array
|
|
*
|
|
* @see [Maximum value](https://en.wikipedia.org/wiki/Maximum_value)
|
|
*
|
|
* @example findMaxRecursion([1, 2, 4, 5]) = 5
|
|
* @example findMaxRecursion([10, 40, 100, 20]) = 100
|
|
* @example findMaxRecursion([-1, -2, -4, -5]) = -1
|
|
*/
|
|
function findMaxRecursion(arr, left, right) {
|
|
const len = arr.length
|
|
|
|
if (len === 0 || !arr) {
|
|
return undefined
|
|
}
|
|
|
|
if (left >= len || left < -len || right >= len || right < -len) {
|
|
throw new Error('Index out of range')
|
|
}
|
|
|
|
if (left === right) {
|
|
return arr[left]
|
|
}
|
|
|
|
// n >> m is equivalent to floor(n / pow(2, m)), floor(n / 2) in this case, which is the mid index
|
|
const mid = (left + right) >> 1
|
|
|
|
const leftMax = findMaxRecursion(arr, left, mid)
|
|
const rightMax = findMaxRecursion(arr, mid + 1, right)
|
|
|
|
// Return the maximum
|
|
return Math.max(leftMax, rightMax)
|
|
}
|
|
|
|
export { findMaxRecursion }
|